algorithmic modeling for Rhino
ehm...no..i dont think so-
i need branch {A;B;0}, {A;B;1} and {A;B;2} to add together such that if there are 12 items in each list, after the edition there are still 12 items- each list has one True and the rest False so afte the edition there will be three True and the rest False(given that the Trues are in different index positions. the right-most panel in my picture shows the result i want to get from addig th three lists.
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