algorithmic modeling for Rhino

Experimenting with Kangaroo and Galapagos.

No real design intent, catenary vaults with kangaroo minimising solar incidence with Galapagos.

Optimisation runs for around 5 minutes

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Comment by ML Smile on April 13, 2018 at 1:58pm

Great Nick
That's what I'm trying to do!!
Please, can you show me how did you do that?

Thank you in advance :)

Comment by Sherif Abd El halim on November 24, 2013 at 7:32pm

good job

can you share the script of the simulation ?

Comment by Nick Tyrer on November 23, 2013 at 6:49am

Cool thanks Artyom, i feel bad making you consult the manual on my behalf, i will have to properly test it all, to work out when/where i would need each one. 

Comment by Alex Bocchi on November 21, 2013 at 6:11am


Comment by Artyom Maxim on November 20, 2013 at 1:05pm

And the GH timer sets the timing for calculating GH iterations, i suppose.

Comment by Artyom Maxim on November 20, 2013 at 1:03pm

And the timestep is "how far through time the system moves at each iteration" as stated in the manual.

Comment by Nick Tyrer on November 20, 2013 at 6:38am

and what is its relationship to TimeStep and the Timer?

Comment by Artyom Maxim on November 20, 2013 at 6:29am
I would say, the number of subiterations is the number of cycles that kangaroo does within one GH iteration.
Comment by Nick Tyrer on November 20, 2013 at 6:21am


Its not the gravity, i wanted to be able to move the anchor points, so the anchor points have to begin in the right place or it all fails. So they follow a little path for movement, that starts in the correct place. The only annoying aspect is resetting them all to 0 each time you reset the calculation.

My limited understanding is that increasing the subiterations, means that kangaroo completes the simulation internally with no visuals, speeding it up. And the mesh that is output is always the final catenary form that has found equilibrium.

Comment by Arthur Mamou-Mani on November 20, 2013 at 5:21am

Are you changing the values of the gravity with Galapagos? Does it mean that each Kangaroo iteration in this case is the final one? 





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