"surfaces" ? Our teacher said to place the truncation according to this relation : Capture%20d%E2%80%99%C3%A9cran%202016-05-01%20%C3%A0%2008.03.46.png I already make the five platonic polyhedrons in Rhino.
Best,
Nastia …
thankssssss
.74-.80 may is ok not big differents .. but i have to control each group of triangles :)
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sorry the version is
rhino 4.9
gr 0.8.0004 version
thanks :)
Added by architecture at 6:26am on December 20, 2011
ded a circle and been able to draw the two lines and cull out the correct distances but do not know how to pull out those two original lines - the one from the starting point to the circle division + the circle division to the end point.
To recap - I'm looking for a way to have 2 lines = 80" when the direct path between two points is 60". I do not want the 2 new lines to be equal in length but variable lengths.
thanks!
_patrick
…
g these times itself). If it works on selection alone, it would probably implement faster.
Theoretically, does this mean the total solving time of the definition is the 'chain of components' that takes the longest time? In the picture above, it would be the chain consisting 'point-curve-divideDistance'?
Because that still adds up only to 97%, I am assuming the Point and Slider component start solving in parallel, and the two Divide components also start solving in parallel?…
tries, of different types, both annotation objects and curves, won't it be slow to iterate through all these objects for each rectangle?
I use 0.6.X but i'm soon making the shift to 0.7.X…