curve B
B1--------------------------B0
You define distances:
|A0 B0|
|A0 B1|
|A1 B0|
|A1 B1|
And find the smallest one. Then, based on the number of the shortest distance:
Flip A, Leave B
Flip A, Flip B
Leave A, Leave B
Leave A, Flip B
A more advanced metric would be to create all 4 blends, then pick the one that is shortest. Maybe that works better for what you want, maybe not.
--
David Rutten
david@mcneel.com…
Added by David Rutten at 8:09am on February 11, 2014
f the mesh was self-intersecting everywhere. So instead I used Millipede (isosurface) to get the same undulations, but ignore the complex 'folds', you can see the difference in cross section thickness. I then tessellated it with the inverse pattern of the outer surface.
To make it a single 3d printable mesh, i just deleted a single face on inner and outer skin, then lofted the naked edges. (creating a tiny hole through the model). Therefore creating a single mesh that folds in on itself, not sure if there is a better way of defining the space between two meshes as the solid area...
Full GH (Kangaroo - Meshmachine - Weaverbird - Millipede)
Special thanks to Laurent Delrieu for his interesting offset mesh method that i based my approach on.
http://www.grasshopper3d.com/forum/topics/offset-mesh-problems-with-3d-mesh-with-weaverbird…
Added by Nick Tyrer at 5:25am on December 10, 2015
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g these times itself). If it works on selection alone, it would probably implement faster.
Theoretically, does this mean the total solving time of the definition is the 'chain of components' that takes the longest time? In the picture above, it would be the chain consisting 'point-curve-divideDistance'?
Because that still adds up only to 97%, I am assuming the Point and Slider component start solving in parallel, and the two Divide components also start solving in parallel?…