rray of cables, fasteners and other useless stuff.
PS: one issue brings the other :
There's some components that respect the tree and others that do whatever they want.
For instance imagine 23 line sets that belong to 3 branches (the facade profiles). If you apply Divide curv (say with 7 divisions) you expect to get back 23*7 points in 3 branches....not the case I'm afraid.
However if you apply Eval Curv with just one value for t > you get 23 points in 3 branches.
Moral: more red Russian vodka required (+ a decent cigar)
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Hi Naoki! Use list item to extract 2 and 3 from original list. Cull item 2 and 3 from original list and then list insert (insert your list item in 4 and 5 indexes). Hope helps. Bests.
o three parts:
branch 1:
{0;0} N = 3
{0;1} N = 3
branch 2:
{1;0} N = 5
{1;1} N = 5
branch 3:
{2;0} N = 30
{2;1} N = 30
parthmapper won't change the length of branch, explode tree won't give me two branches in one output
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should not be open).
3. All releases of Rhino 5, Arduino, GH, and FF are the latest as of May 21st.
I Boolean toggled the port open, but I can't seem to get any output to display from the UnoRead component. I was hoping to see values from any of the analog inputs (APin5 depicted) connected as info gets sent back and forth between the Arduino and my comp. I'm getting simultaneous "Hooray" and "Whoops" messages, and I can't pinpoint why. See attached JPG.
Does it have to do with the fact that I have a list of COM ports? Even though I know COM 3 is the correct one as defined in the IDE, do I need to re-declare it in Grasshopper as well? Does the {0} shown impact this output?
Any direction is appreciated.
Thanks - JFig
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That is correct. In reality there are 3 major versions of .NET 1, 2, and 4 (different versions of mscorlib.dll)
Rhino 4 uses .NET 2 which includes 3 and 3.5.
Rhino 5 uses .NET 4
branches in each A's list of B's, or remove its ends etcso that if I want to remove the last B in every A{0;1},{0;2},{0;3},{0;4},{0;5},{0;6}{1;1},{1;2},{1;3},{1;4}{2;1},{2;2},{2;3},{2;4},{2;5}would become{0;1},{0;2},{0;3},{0;4},{0;5}
{1;1},{1;2},{1;3}
{2;1},{2;2},{2;3},{2;4}I guess the question is do I need to figure out the cull pattern- each B may have different lengths...…