brae of the system. The triangular frames are defined through the connection of points on the outer 3 rails. The central spine with the outer frames form a coherent structural system.…
5 chunks ->
1 chunk with all items that divide circle into 3 parts.
2 chunk with all items that divide circle into 4 parts.
3 chunk with all items that divide circle into 5 parts.
etc. until items that divide circle into 7 parts.
Hope you can understand my problem.
I added image of definition below.
Thanks!
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But say the values you remove aren't consecutive, like if you remove 2, 5 and 7 and want to replace them with values in their original list location...
{0;0;0;0 -1, 2... 19 ) N=5
i know is basic but im still trying to get my head around lists/trees and how to manipulate them properly
thanks for your time
sn…
cture, Rhino treats them as a single flat list. For example a surface can have 10 rows and 6 columns of control-points, resulting in a list of 60 points.
But 10 times 6 isn't the only way to get to 60. If you want to make a surface out of a list of 60 points, you'll also have to tell Rhino how those 60 points should be interpreted in terms of a grid. It could be 2*30, 3*20, 4*15, 5*12, 6*10, and all of the aforementioned products the other way around.
Sometimes there's only one way for a number of points to fit into a rectangular grid. For example if you provide 49 points, then 7*7 is the only way to make it work, but these cases are rare so we always demand you give us all the information required to actually make a rectangular grid of control-points from a linear collection.
As for "Why is it, sometimes we need to attach additional value into it?", this is usually because when you divide a domain or a curve into N segments, you end up with N+1 points. For example take the domain {0 to 5}, and divide it into 5 equal subdomains. You end up with {0 to 1}, {1 to 2}, {2 to 3}, {3 to 4} and {4 to 5}. However there are six numbers that mark the transitions between these domains 0, 1, 2, 3, 4 and 5. This is why you often have to add 1 to the UCount, because the number that controls the UCount often results in N+1 actual points.…
Added by David Rutten at 8:30am on December 25, 2014