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Added by kavehoshkooh at 3:25pm on September 11, 2015
ts will basically be a set of different ellipses:{a1, a2, b1, b2} (with different properties) From that i want to create random Lists of let’s say 15 items (ellipses) Something like that {a1, b2, b1, a1, a2, b1, b1, a2, a1, b1, b2, a1, b2, a1, a1}. But I want to be able to create some constrains. So for example if I have a1 I will be able to have next a2 or b1 but not to b2. I am not sure if this is possible in grasshopper and i was messing around with some logic components but without any luck.
Any help will be greatly appreciated.
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nt B2[i] so B1[i]<=0 means no new connections allowed for point i ,so point i is deleted from B1, B2 updated accordingly.
Initialization:
B1: max number of connections x number of points
B2: all the points
B3: nothing (well null or something, need to create the branch)
Algo:
Get first point in B2, get his allowed number of connections N in B1, find N closest points in B2, create lines in B3, update B2 accordingly. Erase points with max connections (including the first point)
Next
Stop when no points available
At end of loop, B3 stores the created lines.
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, a1200)}) Is there any way I can make this list into {a1, a2, a3, a4, -a5, -a6, -a7, -a8, a9, a10, a11, a12, -a13, ..... , a1200} ? ( 4 positive signs then 4 negative signs and so on) - alternating every nth in general.
or
2. Is there any way (workaround) to get negative angle value from 2 vectors? I know 'ANGLE (of 2 vectors)' component by itself doesn't work and I know why too. I have feeling that the reflex angle output might be useful but again, matter of list manipulation.
Any help would be greatly appreciated. Thanks in advance.
Hyo
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nt to multiply the number of items in the list A, so at the end I will end up with the same number of elements in each lists.
e.g. (for branch 1 in list A I want to have two times the same curve, and the same for the branch 2 and so on )
List A (Data with 88 branches)
{0} N=1
{1} N=1
{2} N=1
{3} N=1...
List B (Data with 88 branches)
{0} N=1
{1} N=2
{2} N=2
{3} N=1...
NEW List A (Data with 88 branches)
{0} N=1
{1} N=2
{2} N=2
{3} N=1...
Any suggestions about how to do this?
Thank you,
Martha
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