EC
1. Between hours 1:00 to 24:002. Current document units is in Meters3. Conversion to Meters will be applied = 1.0004. [1 of 7] Writing simulation parameters...5. [2 of 6] No context surfaces...6. [3 of 6] Writing geometry...7. [4 of 6] Writing materials and constructions...8. [5 of 7] Writing schedules...9. [6 of 7] Writing loads and ideal air system...10. [7 of 7] Writing outputs...11. ...... idf file is successfully written to : c:\ladybug\Freeformtower_IDF\EnergyPlus\Freeformtower_IDF.idf12. 13. Analysis is running!...14. ......
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15. 16. Program Version,EnergyPlus-Windows-64 8.1.0.009, YMD=2015.04.04 23:39,IDD_Version 8.1.0.00917. 18. ************* IDF Context for following error/warning message:19. 20. ************* Note -- lines truncated at 300 characters, if necessary...21. 22. ************* 577 Zone,23. 24. ************* Only last 1 lines before error line shown.....25. 26. ************* 578 Freeformbuilding27. 28. ** Warning ** IP: IDF line~578 Comma being inserted after:" Freeformbuilding" in Object=ZONE29. 30. ** Severe ** Out of range value Numeric Field#5 (Type), value=0.00000, range={>=1 and <=1}, in ZONE=FREEFORMBUILDING31. 32. ************* IDF Context for following error/warning message:33. 34. ************* Note -- lines truncated at 300 characters, if necessary...35. 36. ************* 586 BuildingSurface:Detailed,7341.
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I was thinking to use somehow slider and animate option....but without luck
Any idea would be appreciated…
as follows.
We have a grid which consists of a collection of columns, where each column consists of a list of points. You said flattening is out of the question, so we need to cull items from each list individually.
Let's say our culling pattern is KDDDKDD (repeat as needed). K = Keep, D = Ditch. If a column contains 18 points, the pattern needs to be repeated until it is 18 items long. In this case:
1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18
K D D D K D D K D D D K D D K D D D
We can now cull each column, but they will all be culled in the same way. By shifting the pattern one more index for each column, we can cycle the culling.
The fix incidentally is to Shift the pattern PRIOR to repeating it. Then it works as expected:
--
David Rutten
david@mcneel.com
Tirol, Austria…
Added by David Rutten at 2:49pm on October 2, 2013
are on their own paths, but the first branch contains 3 curves and the second one 2 curves. If you want the same result for all pairs of curves you'd need to split up the first and second branches, so that all curves are on their own branch.…
Added by Lars Renklint at 4:33am on September 6, 2009
etting when I merge the three trees, but what I would like to get is:
essentially a tree with 27 branches, each with a single list of either 11 or 21 points.
{0} (N=11)
{1} (N=11)
...
{10} (N=21)
{11} (N=21)
...
{17} (N=11)
{18) (N=11)
{27} (N=11)
Any help would be greatly appreciated.
All the best,
Matt
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Added by Matt Schmid at 3:06pm on December 4, 2010
number of divisions on that curve as in the defintion (i.e. by 4). The offset in the def is slightly different and should cull two or three more curves as in the lists that show my aim below.
Basically I want to look into each branch of the groups of points from each closed curve . Marking in a list whether it contains a one or a zero (0= outside 1 = coincidents).
{0;0}0. 21. 22. 23. 2 {0;1} 0. 01. 22. 03. 2 {0;2}0. 01. 02. 03. 0 {0;3}0. 21. 22. 23. 2 {0;4}0. 21. 22. 23. 2 {0;5}0. 21. 22. 23. 2 {0;6}0. 01. 22. 23. 1 {0;7}0. 21. 22. 03. 0 {0;8}0. 21. 22. 23. 2 {0;9}0. 21. 22. 23. 2 {0;10}0. 21. 22. 23. 2 {0;11}0. 21. 22. 23. 2 {0;12}0. 21. 22. 23. 2 {0;13}0. 01. 22. 23. 0 {0;14}0. 21. 22. 23. 2
I want to create a list from these points. That marks each curve that pokes out, in a cull pattern as such:
20022210222202
Using a 1 where there are co-incidents in the curve points and the boundary. A 2 for true (outside points) and a 0 for containment. So I might be able to use the 1 in future developments - however if a true false list is easiest I can live with that.
So could I use F(x) function? - to look for 0 or 1's in each bunch of points and thus list as such for a cull pattern? or will Path mapper help me here? Or can I rely on simply grafting and splitting??
I am usure of the neatest solution and would love to learn. Hope you can direct me.rgrds
J.…
nique name like in your example {0;0},{0;1},{0;2},{0;3} where each path contains 11 elements(curves,points,values,etc)
so if you want to restructure the structure first right click on path mapper and take create null mapping which reads your current path structure into the component
after that you can additional write on the left side to the existing path (i) as variable for the elements and then on the right side type in the structure you want to achieve
maybe {A;i}(B) so after that you have 11 paths where each have 3 elements
hope that helps…
(18, 11, 0, 17), also put in the assembly component.
How can I know which value of the reaction forces correspond to which support?
In the manual is stated that when the reaction force component is used, than the values are displayed in ascending sequence of the corresponding nodes.So if I input the support nodes like thispoint with index 18point with index 11point with index 0point with index 17are the reaction forces displayed like this (per loadcase)?0 - reaction forces in point with index 01 - reaction forces in point with index 112 - reaction forces in point with index 183 - reaction forces in point with index 17
Thanks!
BestLara…