a furniture with diagonal joints.
Let me express myself graphically.
http://www.plataformaarquitectura.cl/2011/01/28/munich-l%e2%80%99illa-diagonal-dear-design/05-78/
take a look at the picture. how could I make panel wood with a diagonal cut in each end, so when I place them together they fit perfectly?
a diagonal cut with a CNC machine?!
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is allowed to be increased, depending on the air speed as specified in Table 5.4.2.4, which can be as high as 2.2 degree.
So, I assume the height of the "hump" is about 2.2 degrees from the upper acceptability limit (80% or 90%).
Appreciate your advice if the understanding here is not correct.
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thankssssss
.74-.80 may is ok not big differents .. but i have to control each group of triangles :)
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sorry the version is
rhino 4.9
gr 0.8.0004 version
thanks :)
Added by architecture at 6:26am on December 20, 2011
ven if the number of panels inside each cell varies. The current solution works when the number of panels inside each cell is always two or other same numbers, but it wouldn't work if the number of panels inside frames are different in each cell. It would be perfect, if numbering of panels are automatically added correctly next to the cell number based on the number of panel division instead of feeding the fixed number.
To take an example, let's assume that the cell #80 has three panels and the #81 has two ones. In this case, three panels within the cell #80 would be numbered like 80-1, 80-2, 80-3, while two panels within the #81 would be numbered such as 81-1 and 81-2 automatically. …
rence not set to an instance of an object. (line: 80)
Both .dlls appear to have been successfully imported.
Thanks in advance,
Charles
RStatSystem rs = ri as RStatSystem;
List<Line> slines = new List<Line>();
foreach(RStatBeam b0 in rs.Beams) { <------ line 80
if (b0.StiffnessMultiplier < 0.3) continue;
slines.Add(new Line(b0.P0.ToPoint3d(), b0.P1.ToPoint3d())); }
A = slines;
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ded a circle and been able to draw the two lines and cull out the correct distances but do not know how to pull out those two original lines - the one from the starting point to the circle division + the circle division to the end point.
To recap - I'm looking for a way to have 2 lines = 80" when the direct path between two points is 60". I do not want the 2 new lines to be equal in length but variable lengths.
thanks!
_patrick
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