omponent that increases in the x-axis (example below).
A1 A2 A3 A4 A5 etc...B1 B2 B3 B4 B5 etc...C1 C2 C3 C4 C5 etc...D1 D2 D3 D4 D5 etc...
This is as far as I've gotten:
I have collected my points on the grid into a "List Length" component and input that into a "Series" which input into a "Function" with the expression Format("A{0}",x). The result labeling resembles the example below.
A1 A2 A3 A4 A5
A6 A7 A8 A9 A10
A11 A12 A13 A14 A15 etc...
Any help is appreciated.
Thank you in advance.…
. The rules to dispatch the lines are the next:
I start with a list that alternate true/false; like that: true, false, true, false.
If the angles between those lines are greater than 89° I want to inverse the next part of the list:
True, False, True, False, True, False,...
become
True, False, [>89°] False, True, False, True, [>89°] True, False,...
I managed to create a true false list, to check for the greater than 89° angle, to separate the lines relatively to the angles, but I don't know how to inverse part of the list at certain index.
(In the picture, I have written 90° but it should be 89°, I check for greater than 89° and not equal to 90° because in the real rhino model, the lines won't be exactly orthogonal)
If you have another idea to to reach the same result, it's also okay, I tried to find rules to solve the problems, but I may have overlooked other solutions !
And if there is some part of the patch that are correct but there is easier solution, I would love to learn as I am still new to grasshopper.
Thanks for taking the time to read. :)
…
ng long in the x axis and three in the y and they don't all intersect each other... I wrote a script to Boolean difference them but its not working like i want it to . I included a rhino result that id like to achieve in the file. THX -ethan
heres the script:
import rhinoscriptsyntax as rs
b1 = []for i in range(b1L): b1.append (x)print b1bb= len(b1)print bbb2 = []for j in range(b2L): b2.append (y)print b2bc = len(b2)print bc
def bool ():....for i in range (bb):........for j in range(bc):............a = rs.BooleanDifference( b1,b2, False).....return (a) a = bool ()…
he code within a limited number of turns. I suggest you check 양방하는법 and learn more interesting things about games. The game is not only challenging and fun, but it also helps to improve cognitive skills such as critical thinking, problem-solving, and pattern recognition. Mastermind has stood the test of time and remains a beloved game for all ages.…
Added by MichaelD0112 at 12:25am on April 10, 2023
nt B2[i] so B1[i]<=0 means no new connections allowed for point i ,so point i is deleted from B1, B2 updated accordingly.
Initialization:
B1: max number of connections x number of points
B2: all the points
B3: nothing (well null or something, need to create the branch)
Algo:
Get first point in B2, get his allowed number of connections N in B1, find N closest points in B2, create lines in B3, update B2 accordingly. Erase points with max connections (including the first point)
Next
Stop when no points available
At end of loop, B3 stores the created lines.
…
nologically label them (there are currently 65 points and this is labelled as in the file i've attached). However, what i'm actually after is to reformat these points into an x and y style grid.(a1, a2, a3, a4, a5)(b1, b2, b3, b4, b5)(c1, c2, c3, c4, c5)(d1, d2, d3, d4, d5) etc.Any ideas/help how this can be made possible would be great.Thanks in advance…