jaja, I tried a brute force method using Mathematica...lol I give it the list of values and it gave out instantly:
(1/9) * (57 + 48 * n + 15 * Cos((2 * n * Pi)/3) + Sqrt(3) * Sin((2 * n * Pi)/3) )
Added by Jesus Galvez at 7:42am on November 27, 2012
9 8 7 6
5 4 3 2 1 0
I am triangulating this surface. I want to select just the red vertices. As you can note, I just need the inner vertices of this surface. I could do it mannually, but if I want to change the mesh density later, I will have to pick all of them manually again later.
Can someone help me?
Tks
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Hello to everybody..
Maybe I didn't explain very well..
Tha question id this can be possible chance the indices of a list of element from 0 to 15 in a list from 1 to 16?
Thanks
Guido Nieri
ved from the source surface.
3. Send the center points to the VB component.
If you send 15 points to the VB component, it will then return 15 * 4 spirals.…
Added by June-Hao Hou at 9:41pm on December 2, 2010
he sunPath component works. For example if you want to simulate the hours from 8 to 16 it means you want 8 hours from 8 to 9, from 9 to 10,.... from 15 to 16 (8 hours duration period) so you get from the sunPath component (using default timeStep 1) the 9 sun position/vectors 8 9 10 11 12 13 14 15 16 (in the image the yellow suns). The things is that if you ask for a smaller timeStep for example 3 = 20 mins then the additional sun position (in the image the orange suns) are added also after the time limit of h16 so probably when you don't want/need. I understand that when you input a time period there is the ambiguity if the hours are the just 9 (the 9 inputs) or the 8 hours included between pairs of hours, but I would make in a way that it is possible to chose if the extra timeStep after the last hour are added or not. Thank you for your comments.
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