of lines, etc) but I can't see a way to add the text I need where I need it. If I could get each line for the print run to generate automatically, I can put the rest in manually, so just need something like:
... ; I would do the previous to this manuallyG1 X10 Y5 Z3
G1 X5 Y5 E5
G1 X5 Y15 E10
... ; I would do the rest manually
for a 5 mm line from [10, 5, 3] to [5, 5, 3], followed by a 10mm line from there to [5, 15, 3]. Any pointers greatly appreciated.
Ewan…
set of planar closed polylines
BB Difference: Difference of a set of planar closed polylines
BB Intersection: Intersection of a set of planar closed polylines
BB XOR: Exclusive or of a set of planar closed polylines
BB Python component dropped (use Node-in-Code instead)
minor bugfixes
Source code is now available on GitHub
Download Bowerbird…
structures. I think you can get นิสัย and learn more about the business. This architectural dance blurs the line between art and engineering. Because complex algorithms form a space that fosters creativity and collaboration. which is an outstanding platform for future business ideas.…
Added by MichaelD0112 at 1:34am on August 14, 2023
est of the best)
Crucial DDR4 2133 ECC (what else?)
4* WD RE 500 in Raid combo (not shown)
Some stupid 2.5'' HD thingy (avoid 2.5'' disks)
No SSD thingy
Corsair CPU cooler (Tequila replaced the OEM liquid: it works)
…
exact formula is inside /lib/skybright.cal if this can help you to find the name.
{ RCSid: $Id$ } { Sky brightness function for sunny and cloudy skies.
Additional arguments required for calculation of skybright:
A1 - 1 for CIE clear, 2 for CIE overcast, 3 for uniform, 4 for CIE intermediate A2 - zenith brightness A3 - ground plane brightness A4 - normalization factor based on sun direction A5,A6,A7 - sun direction }
cosgamma = Dx*A5 + Dy*A6 + Dz*A7;
gamma = Acos(cosgamma); { angle from sun to this point in sky }
zt = Acos(A7); { angle from zenith to sun }
eta = Acos(Dz); { angle from zenith to this point in sky }
wmean(a, x, b, y) : (a*x + b*y) / (a + b);
skybr = wmean((Dz+1.01)^10, select(A1, sunnysky, cloudysky, unifsky, intersky), (Dz+1.01)^-10, A3);
sunnysky = A2 * (.91 + 10*exp(-3*gamma) + .45*cosgamma*cosgamma) * if( Dz - .01, 1.0 - exp(-.32/Dz), 1.0) / A4;
cloudysky = A2 * (1 + 2*Dz)/3;
unifsky = A2;
intersky = A2 * ( (1.35*sin(5.631-3.59*eta)+3.12)*sin(4.396-2.6*zt) + 6.37 - eta ) / 2.326 * exp(gamma*-.563*((2.629-eta)*(1.562-zt)+.812)) / A4;
…
ng long in the x axis and three in the y and they don't all intersect each other... I wrote a script to Boolean difference them but its not working like i want it to . I included a rhino result that id like to achieve in the file. THX -ethan
heres the script:
import rhinoscriptsyntax as rs
b1 = []for i in range(b1L): b1.append (x)print b1bb= len(b1)print bbb2 = []for j in range(b2L): b2.append (y)print b2bc = len(b2)print bc
def bool ():....for i in range (bb):........for j in range(bc):............a = rs.BooleanDifference( b1,b2, False).....return (a) a = bool ()…