would like to group the paths based on their item count (n) values resulting in a tree which should look something like this:
{0;0} (3)
{0;1} (2)
{0;2} (2)
{0;3} (1)
in other words, all paths with 2 items are under one path, all with 6 items in another, and so on.
I feel that the pathmapper should be able to do this very easily but cannot figure out what the expression should be... I have tried searching the forum but have not had much luck!
Any ideas? Thanks a ton!…
ggle A
7. Toggle A
8. Toggle 2
9. Toggle 3
10. Toggle A
11. Toggle A
12. Toggle 3
I was thinking to use somehow slider and animate option....but without luck
Any idea would be appreciated…
ersect (2, 3, 4, 5, 6) with the line and the ones which do not intersect (0, 1, 7). Intersect is done! But how to get the non intersecting vectors (0, 1, 7)?
So I e. g. could deselect vectors 2, 3, 4, 5, 6 so I would display/use only vectors 0, 1, 7 and the bounced ones.
Appreciate your help!
Rudi…
a follow up question... how do I wrap a list onto itself at a certain frequency?
i.e. I want the list {1;2;3;4;5;6;7;8;9}
to become {1,4,7; 2,6,8; 3,6,9} wrapped every 3rd item
Added by Joshua Jordan at 5:30pm on November 17, 2012