Search Results - 11选5开奖结果爱彩乐-『1TBH·COM』11选5前三直最大遗漏多少期--2023年3月19日5时52分52秒.H5c2a3.t93brrchr

Comment on: Topic 'I get an error when I use mesh(+). It is not working..': Just to check the obvious, you are using the at least Grasshopper release .0056, and Rhino 5 Service Release 3?; Added by David Mans to mesh+ at 9:15am on September 26, 2013

Comment on: Topic 'Galapagos + Geco error.': 0.8.0066 5 stagnant and 5 population works for me; Added by Hannes Löschke at 5:35am on February 15, 2012

Comment on: Topic 'data list manipulation': ep is to understan the logics of what you want to do, in your case, build 4 point surfaces (u also need to know the right direction to build the surfaces). Then you can write an hipotetic list (by hand in a paper) of what you want. In your case the list was (0, 1, 3, 2) (2, 3, 5, 4) (4, 5, 7, 6), etc... if you can imagine building 2 lists, each one with the sequences (0, 2, 4, 6, etcc) and (1, 3, 5, 7, etc..) then you can manage with shift and graft to finally have four lists. A( 0 1 2 3 ...) B (1 3 5 etc..) C(3 5 7 etc..) D (2 4 6 etc..). And to achieve the 2 first lists, you need to get the odd and the pair numbers. The cull pattern does that amazingy well. With a pattern True-False you get de pair numbers, and with the False-True pattern you get de odd numbers. Hope it was clear enough…; Added by Pep Tornabell at 5:32am on November 19, 2009

Topic: bake issue: m any idea ? -- Gennaro…; Added by gennaro senatore at 12:32pm on July 3, 2011

Topic: Data Tree or List of List C#: output will show a tree with 3 branches of 4 integers each that I can pass on to other components. What is the best way to do it? I have tried creating a tree and using a for loop to do so, but it didn't work. Thank you for your help. …; Added by Godjenka at 8:25pm on December 23, 2015

Topic: Model stifness matrix singular: 7, 9, 12 and 13 to be able to rotate freely around the y axis at nodes 2, 3, 6, 7, 10 and 11 respectively. The last 2 conditions, for elements 12 and 13, doesn't give any problems, but the first 4 does. Any help? …; Added by Ruy Sevalho Goncalves to Karamba3D at 12:12pm on April 13, 2016

Topic: How to recompose m-lists of n-points, jumping from one list to the last, with a fixed interval the items??: the one-but-last list [4]. After running out of the n- items avalaible it should continue with the second item of list 0 and so on for all items on all the lists. Intput, six lists of 30 items each [0] (n=30) [1] (n=30) [2] (n=30) [3] (n=30) [4] (n=30) [5] (n=30) Output, 18 lists of 10 items each [0],i=0;[5],i=4; [4],i=7;... [0],i=1;[5],i=5; [4],i=8;... ... [5],i=1;[4],i=5; [3],i=0;... I thought perhaps the weave component or the relative tree item component but didn't manage to figure out how to compose the mask. I couldn't find much on how to use these. I guess it should wrap the lists, but not the items. Any help would be greatly appreciated.…; Added by Thorsten Lang at 2:27am on January 24, 2011

Topic: Bespoke slicer - last step: of lines, etc) but I can't see a way to add the text I need where I need it. If I could get each line for the print run to generate automatically, I can put the rest in manually, so just need something like: ... ; I would do the previous to this manuallyG1 X10 Y5 Z3 G1 X5 Y5 E5 G1 X5 Y15 E10 ... ; I would do the rest manually for a 5 mm line from [10, 5, 3] to [5, 5, 3], followed by a 10mm line from there to [5, 15, 3]. Any pointers greatly appreciated. Ewan…; Added by Ewan Dorris at 1:02pm on March 23, 2017