and 17% using the 2 vertical lines. The galapagos works well, finds the solution. Is there a way for galapagos to sort them also, so for example, the area 44% to be the first from the left, the area 39% to be second from the left and the area 17% the third?
As you can see it sorts the three areas randomly (here the 17% area was placed in the middle and not in the right)
this is the rectangle
this is the ghx file…
e range of materials, including heavy-duty fabrics. They offer a range of embroidery machines that cater to different needs and budgets.best embroidery machine for custom designs…
e material I want.
There are some command I don't understand inside the csv file, just wonder if you know how to read time and edit them?
e.g. for the data of concret :
#;;;;;;;;#;;;E;G;gamma;alphaT;fcd;my#;family;name;[kN/cm2];[kN/cm2];[kN/m3];[m/(mC°)];[kN/cm2];[-]#;"according to EN 1992-1-1; revision 2009-07-01:";;;;;;;;Concrete;Concrete;3100;1291.67;25;1.00E-05;1.67;0.2;Concrete;C12/15;2700;1125;25;1.00E-05;0.8;0.2;Concrete;C16/20;2900;1208.33;25;1.00E-05;1.07;0.2;Concrete;C20/25;3000;1250;25;1.00E-05;1.33;0.2;Concrete;C25/30;3100;1291.67;25;1.00E-05;1.67;0.2;Concrete;C30/37;3300;1375;25;1.00E-05;2;0.2;Concrete;C35/45;3400;1416.67;25;1.00E-05;2.33;0.2;Concrete;C40/50;3500;1458.33;25;1.00E-05;2.67;0.2;Concrete;C45/55;3600;1500;25;1.00E-05;3;0.2;Concrete;C50/60;3700;1541.67;25;1.00E-05;3.33;0.2;Concrete;C55/67;3800;1583.33;25;1.00E-05;3.67;0.2;;Concrete;C60/75;3900;1625;25;1.00E-05;4;0.2;;Concrete;C70/85;4100;1708.33;25;1.00E-05;4.67;0.2;;Concrete;C80/95;4200;1750;25;1.00E-05;5.33;0.2;;Concrete;C90/105;4400;1833.33;25;1.00E-05;6;0.2;#;;;;;;;;;
DO you know what does [#;;;E;G;gamma;alphaT;fcd;my] stand for? what is E? G? gamma? alphaT? fcd? my? I know I need to find the according data for my specific material but I am not sure what they mean.
Thank you very much…
ake them appear
2. Also I haven't been able to trim the boxes on these edges
3. I want to randomly select and group a percentage of the boxes, having at the end 2 groups of boxes (i.e. 25% and 75%).
I will appreciate if someone can help me with this.…
where each branch contains all the points generated by dividing each curve, so if you divide into 10 segments, you'll get:
{0;0}(N = 11)
{0;1}(N = 11)
{0;2}(N = 11)
{0;3}(N = 11)
{0;4}(N = 11)
Where the second integer in the curly brackets refers back to the index of the curve in the original list.
Another way to look at this data is to see it as a table. It's got 5 rows (one for each original curve) and 11 columns, where every column contains a specific division point.
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David Rutten
david@mcneel.com
Poprad, Slovakia…