David's past 2 to the 12
then me 2 to the 11 ( I need a life)
I'd say you're a shoo-in for 3rd with 2 to the 10
After that it gets a bit hazy, probably Luis then Giulio. But who's counting :)
output will show a tree with 3 branches of 4 integers each that I can pass on to other components. What is the best way to do it?
I have tried creating a tree and using a for loop to do so, but it didn't work.
Thank you for your help.
…
not sure about my method used to obtain the result.I think is really complex; do you know a smart method to simplify all my equation?
thanks guys!! :D…
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} (N=11) {0;1} (N=11) {0;2}(N = 11) {0;3}(N = 11) {0;4}(N = 11)
2. I run the Points that are coming out from the Divide Curve Components through the Path Mapper components with this definition:
{A;B} (i) > {A} (i)
3. I run data coming out from Path Mapper component through:
a) Parameter Viewer component and the result is:
{0} N=11 (data with 1 branches)
b) Point > Panel and the result is:
collection of 11 point (N=11) which is the exactly the same as the collection of point belonging to {0;4} (N = 11).
So, here is the question:
why the collection of points coming out from the Path Mapper {A;B} (i) > {A} (i) component is the same as the collection of points belonging to the curve {0;4}(N = 11) ?
Anyway ... It 's the first time I ask a question here... so I would like to thank you for what you do with your work! Thank you! You are really great!…
e now contains (40x3x11=)1320 points with a branch structure of {0-39,0-2} i.e
{0;0}
{0;1}
{0;2}
{1;0}
...
{39;2}
with each branch containing 11 points.
I now want to create lines from the points on line {x;0} to {x;1}, {x;1} to {x;2}, and {x;2} to {x;0}, which will give me a triangular grid on each triangle. How do i do this? I think I need to split the tree 40 times to give me 40 single layered trees but I imagine there's a cleverer way of doing this!
This feel like it should be simple, but I;m having trouble working with the double-layered branch structure. Any help would be greatly appreciated!
Thanks,
Matt…
First use a series component with start=1, step=42, count=3
Use the output to create a new series component with start=existingseries, step=1, count=11
onsecutive points at the same height then your 'Break at discontinuities' component eliminates the middle point completely and then the 'Interpolate Curve' component gives a much bigger bump in the wrong direction. This was enough to get curves to meet from opposite sides.
I fixed this by changing the heights to 1.1 or 2.9, rather than 1.0 and 3.0, but it took a little while to work it out! Sigh.
I attach a new version. But I actually preferred it as it was before. See what you think!
Bob
p.s. in the first list, elements 11, 12, 23 and 24 go from 1 to 3; elements 17 and 18 go from 3 to 1. In the second list, elements 6, 17, 18 and 29 go from 1 to 3; elements 12 and 23 go from 3 to 1. Given the above fix, these can be easily seen.…
Added by Bob Mackay at 10:40pm on November 24, 2015