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} (N=11) {0;1} (N=11) {0;2}(N = 11) {0;3}(N = 11) {0;4}(N = 11)
2. I run the Points that are coming out from the Divide Curve Components through the Path Mapper components with this definition:
{A;B} (i) > {A} (i)
3. I run data coming out from Path Mapper component through:
a) Parameter Viewer component and the result is:
{0} N=11 (data with 1 branches)
b) Point > Panel and the result is:
collection of 11 point (N=11) which is the exactly the same as the collection of point belonging to {0;4} (N = 11).
So, here is the question:
why the collection of points coming out from the Path Mapper {A;B} (i) > {A} (i) component is the same as the collection of points belonging to the curve {0;4}(N = 11) ?
Anyway ... It 's the first time I ask a question here... so I would like to thank you for what you do with your work! Thank you! You are really great!…
First use a series component with start=1, step=42, count=3
Use the output to create a new series component with start=existingseries, step=1, count=11
ll these 12500 points.
Group 1 would represent the point located at 0, 5, 10, 15, 20 etc.
Group 2 - 1, 6, 11, 16, 21 etc.
Group 3 - 2, 7, 12, 17, 22 etc.
Group 4 - 3, 8, 13, 18, 23 etc.
Group 5 - 4, 9, 14, 19, 24 etc.
I can create the pattern but the selection of points are all the points in row 0 and then all the points in row 5 and so on.
I would like the selection of points to start at the bottom left, and sequentially continue to the right and then continue on the 2nd row (left to right & bottom to top). i am hoping the pattern i am trying to achieve is more understood with the quick screen capture I uploaded.
the end goal is to be able to select all the points in the grid that are in each pattern.
Thanks in advance for any guidance with this. …
Added by Alyne Rankin at 6:53am on October 11, 2017
is shorthand for [0 to 8].
> 10 Any number larger than X. This notation is shorthand for [11 to infinity].
>= 5 Any number larger than or equal to X. This notation is shorthand for [5 to infinity].
--
David Rutten
david@mcneel.com
Seattle, WA…
Added by David Rutten at 9:27pm on November 3, 2013
output will show a tree with 3 branches of 4 integers each that I can pass on to other components. What is the best way to do it?
I have tried creating a tree and using a for loop to do so, but it didn't work.
Thank you for your help.
…
Both a date and a time (11:35 on September 4th, 2010)
The .NET DateTime structure only really supports the third. It counts the number of 'ticks' (1 tick = 100 nanoseconds) since midnight on January the first in the year 1. It does not support any moment in history before the year 1, it does not support any date beyond the year 9999 (ok, not a big drawback that one) it does not support calendars other than Gregorian, it does not support time zones, it does not allow you to just specify a time only and leave the date blank or vice versa.
Some of these shortcomings can be hacked onto the structure, basically by hijacking the tick count and assigning special meaning to certain small tick offsets, but there's always trade-offs with such an approach.…
Added by David Rutten at 6:55am on January 27, 2016
, Thomas Grabner, Allison Weiler
The class is taught in English, fully online in 2 sessions of 3 hours each and an additional Q&A day via email. The course is scheduled between 8:00 and 11:00 UTC. This means that it is scheduled between 10:00 and 13:00 for Central European Summer Time (CEST) and between 16:00 and 19:00 for China Standard Time (CST – Beijing time).
Participants are expected to have a basic understanding of Grasshopper. Familiarity with Autodesk Ecotect is not required. You will be able to ask questions in the class through a live chat designed to give participants support on theory and exercises developed during the course.…