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(kavehoshkooh2290@gmail.com)بسیار متشکرم
Added by kavehoshkooh at 3:25pm on September 11, 2015
, so using distance to centre point, you can give all the useless values a 1. Cutting down the values you actually need to work out by 80%. Which is helpful when approaching 1 million points.…
ng long in the x axis and three in the y and they don't all intersect each other... I wrote a script to Boolean difference them but its not working like i want it to . I included a rhino result that id like to achieve in the file. THX -ethan
heres the script:
import rhinoscriptsyntax as rs
b1 = []for i in range(b1L): b1.append (x)print b1bb= len(b1)print bbb2 = []for j in range(b2L): b2.append (y)print b2bc = len(b2)print bc
def bool ():....for i in range (bb):........for j in range(bc):............a = rs.BooleanDifference( b1,b2, False).....return (a) a = bool ()…