where each branch contains all the points generated by dividing each curve, so if you divide into 10 segments, you'll get:
{0;0}(N = 11)
{0;1}(N = 11)
{0;2}(N = 11)
{0;3}(N = 11)
{0;4}(N = 11)
Where the second integer in the curly brackets refers back to the index of the curve in the original list.
Another way to look at this data is to see it as a table. It's got 5 rows (one for each original curve) and 11 columns, where every column contains a specific division point.
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David Rutten
david@mcneel.com
Poprad, Slovakia…
ke she is (a serie of 12 numbers) but if the input is 11 ( i wanted to delet the middle position of the serie)The question is: HOW can i create a solution with an IF Compotent. Like if is true, go forrward with my list of 12 indexes, but if it`s not clear the middle value, to get 11 values, and go forrward with that one!
thx for any help ( i hope with the attaked image, it´s more clear)…
5 8, and then the following values are obtain as the last one (8) plus 3, then this last one (11) plus 5, and then this last one (16) plus 8, and then it starts again: 24+3, 27+5, 32+8...
Thanks
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Added by Jesus Galvez at 5:17am on November 27, 2012
ve a Vertex [V] connected to four other Vertexs [N1-N4].
Each of the has a Value:
V ... 1
N1 ... 5
N2 ... 3
N3 ... 8
N4 ... 11
The Average Filter would set the Value of [V] to
(1+5+3+8+11)/5 = 5,6
The Median Filter would Sort Values and pick the middle one
1,3, [5], 8, 11
Hope that helped...…