elementary; you can see how I picked out 2 of the pentagon's sides individually. This is by far not the best way to do this.
The proper way is to use a an index pattern to pick out sides 1 & 2, 2 & 3, 3 & 4, 4 & 5, and 5 & 1, and then pass these pairs to the fillet routine. There is a way to do this but I couldn't remember the method. …
ow do you sort data trees with distinctive number of list items in each branch?
In this example, there are 161 branches with three distinctive number of list items, 3, 4, and 5. I want to know if there is another way to sort out this data tree into this way: 3 vertices {0;0}, {0;1}, {0;2],...4 vertices {1;0}, {1;1}, {1;2},... 5 vertices {2;0}, {2;1}, {2;2},...
2. Is there a way to sort our surfaces based on number of distinctive list items automatically? For example, if there are surfaces with 3, 4, 5, 6, and 7 vertices, I want to make five branches with the same number of vertices automatically.
I hope my questions make sense...
Thank you!
Dongyeop …
Added by Dongyeop Lee at 12:14pm on October 3, 2016
dimension of matrices must be identical) and division is the same as multiplication (dimension must be in the order of A(mxn)*\/B(nxk) where n is the common dimension): to divide one element by another you just multiply it by 1/value (part or all of the elements can multiply while part or all of the elements divide):
so for example matrix addition of matrices A(2x2): {2,-1}{1,2} and B(2,2): {3,-5}{4,-2} will result in matrix C(2x2):{5,-6}{5,0}. subtraction of those matrices will result in D(2x2): {-1,4}{-3,4}
Division of matrices A(2x2): {2,0.5}{2,4} and B(2x1) :{2}{2} will result in matrix C(2x1): {1+0.25}{1+2}={1.25,3}. Multiplication of those matrices will result in D(2x1):{4+1}{4+8}={5,12}.…