r-workshop programme will focus on the design and 1:1 fabrication of an interactive pavilion for the 2012 International Festival of Electronic Language (FILE). Located on Avenida Paulista, the pavilion will react to light sensors and human activity, so as to transform and create a range of different lighting and spatial effects, triggering further movement and producing an interactive feedback loop of behaviour and response. To accommodate this responsiveness, the design should be developed using recursive scripting, associative modelling and digital fabrication.
Each workshop will focus on a different phase of the pavilion’s design and construction. Instruction will be led by Rob Stuart-Smith of Kokuggia and Tristan Simmonds of Simmonds Studio, with Lawrence Friesen of Generative Geometry, Anne Save de Beaurecueil and Franklin Lee of SUBdV, together withand other AA tutors, as well as local structural engineers and set-designers. Each workshop will offer introductory instruction in computational design - Grasshopper, (GECO, Firefly) and Arduino, and digital fabrication, while advanced instruction will be offered to participants undertaking multiple workshops.
Workshop 1 will develop design variations in small models, as well as material and structural scale modeling, testing and initial 1:1 prototyping, following computational and digital fabrication instruction. Workshop 2 will produce 1:1 prototyping. Following computational and digital fabrication instruction, it will explore the mechanics and electronics of the light-sensors and motors that generate the transformations of the pavilion. Workshop 3 will fabricate the final elements, working directly with manufacturers, testing partial assemblies. Advanced development of all circuits and Arduino scripts will take place following computational and digital fabrication instruction. Workshop 4 will focus on the final assemblage of the pavilion on site.
www.aaschool.ac.uk/saopaulo.
OTHER WORKSHOPS
Workshop 2: 4–13 January 2012
Workshop 3: 3–12 April 2012
Workshop 4: 3–12 July 2012
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d some help with this:)
Here's the array: Dim arr0() As Integer = {0} Dim arr1() As Integer = {1} Dim arr2() As Integer = {2} Dim arr3() As Integer = {1, 2} Dim arr4() As Integer = {3} Dim arr5() As Integer = {1, 3} Dim arr6() As Integer = {2, 3} Dim arr7() As Integer = {1, 2, 3} Dim arr8() As Integer = {4} Dim arr9() As Integer = {1, 4} Dim arr10() As Integer = {2, 4} Dim arr11() As Integer = {1, 2, 4} Dim arr12() As Integer = {3, 4} Dim arr13() As Integer = {1, 3, 4} Dim arr14() As Integer = {2, 3, 4} Dim arr15() As Integer = {1, 2, 3, 4}
'Create the JAGGED array: Dim jarr()() As Integer = {arr0, arr1, arr2, arr3, arr4, arr5, arr6, arr7, arr8, arr9, arr10, arr11, arr12, arr13, arr14, arr15} What I got as input is a single character hexadecimal value, that I allready converted to an integer.My goal is to use that integer to get the corresponding (sub)array's elements to a list.For instance: if my hex value was "C" (thus the integer is 12)it should output the content of the array named arr12 as a list(Of Integer) :34I purposely created the array this way to be able to get the "subarrays", without having to go in the jagged array(jarr), but still no luck.
Since I'm just beginning with VB, I might be approuching this all wrong...
Can anybody please help me with this?
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As an example: this functionality in Grasshopper (+see attchment):
With regards,
Pieter.…
n.18 CFP).
I nuovi scenari emersi in architettura esigono l’utilizzo di nuovi strumenti che danno la possibilità di analizzare e rendere realizzabili forme non convenzionali. Grasshopper è uno strumento adatto a gestire non solo le forme generate ma anche dati che possono risultare vitali per ottimizzare il progetto e fabbricare elementi digitalmente.
Il corso offrirà ai partecipanti gli strumenti per la modellazione parametrica attraverso l’interfaccia generativa Grasshopper, plug-in del noto modellatore nurbs, Rhinoceros. Attraverso una serie di esercizi che si svolgeranno durante il corso, si spiegheranno i temi fondamentali che stanno alla base della modellazione generativa e del design parametrico applicato all’architettura.
Il corso è rivolto a chi ha già una buona familiarità con la modellazione attraverso Rhinoceros ed ha già una conoscenza base di Grasshopper ma vuole ampliare le proprie competenze nel campo della modellazione parametrica e generativa e si terrà da martedì 04.07.2017 a giovedì 06.07.2017 – dalle 10:00 alle 17:00.
VEGA Parco Scientifico Tecnologico Via della Libertà 12 – Venezia Edificio Porta dell’Innovazione – Piano Terra
Le iscrizioni chiuderanno giovedì 29.06.2017.
Il costo del corso è di: € 270,00 + iva (329,4) per i tesserati, convenzionati e studenti. € 330,00 + iva (402.6) per tutti gli altri partecipanti.
Iscrizioni e info: info@fablabvenezia.org
www.fablabvenezia.org…
n vertice? E.g. start point= 0 - neighbour points 1, 5, 12 as in the sample script attached.
- how do I find all edges/lines/curves of the pentagons starting from a certain vertice? Always towards a neighbour from the certain point.- Generally: how to find lines /curves starting at a certain but same point?
- looking to each pentagon: what would be the meaning in Grasshopper terms for all normal vectors from the center of each pentagon to the outside/inside of the Dodecahedron? How can I direct all vectors in one direction (either outside or inside)? My aim is to offset all pentagons in this sample into the same direction (either in or out).
I would appreciate to get some help.…
d so 36 renders.
The Gray animation controller output a norm which is the time normalized, I used it to move point on Z axis, so to move up the color.
You will have to plug the texure adress to a Gray Bitmap that is pluged to Gray Diffuse then to Gray material ...
Et voilà !
Not so hard
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d of interpenetrating surfaces somewhere:
Now all links (except a possible single ball on the very end of odd numbered ball series) are four balls long, including the jostled ones. Without that step, those items simply don't appear in the output, leaving way too big of gaps to ignore, eventually leaving huge gaps at later stages of segment doubling:
So if I turn the jostling multiplication factor way down it should work imperceptibly:
Ta-dah! The jostling strategy WORKS! Granted, only in this special case where I know I'm dealing with adjacent pairs of worms along a curve, not generic objects arranged in space by some artist.
Now I just need to wrap the multiple Python script components I'm stringing together into one script.
How long does the full 2400 balls take, finally? It took 12 Python scripts that merge pairs, to achieve this breakdown: 2400 -> 1200 -> 600 -> 300 -> 150 -> 75 -> 38 -> 19 -> 9 -> 5 -> 3 -> 2 -> 1. Time was 2 minutes 50 seconds, so there is some extra struggle for 2X as many balls as 1200 that took 1 minute 20 seconds, but only ten more seconds.
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Added by Nik Willmore at 9:06pm on February 17, 2016
ranno durante il corso, si spiegheranno i temi fondamentali che stanno alla base della modellazione generativa e del design parametrico.
Il corso è rivolto a chi ha già una familiarità minima con la modellazione attraverso Rhinoceros e vuole ampliare le proprie competenze verso il campo della modellazione parametrica e generativa, e si terrà da lunedì 13.06.2016 a mercoledì 15.06.2016 – dalle 10:00 alle 17:00.
Potete scaricare qui il PROGRAMMA DEL CORSO.
Il calendario dei corsi è consultabile qui.
VEGA Parco Scientifico TecnologicoVia della Libertà 12 – VeneziaEdificio Porta dell’Innovazione – Piano Terra
Per iscriversi al corso è necessario essere registrati al sito.Per tesserarvi al Fablab Venezia, diventare maker, usufruire dei vantaggi, clicca qui.…
dellatore nurbs, Rhinoceros. Attraverso una serie di esercizi che si svolgeranno durante il corso, si spiegheranno i temi fondamentali che stanno alla base della modellazione generativa e del design parametrico.
Il corso è rivolto a chi ha già una familiarità minima con la modellazione attraverso Rhinoceros e vuole ampliare le proprie competenze verso il campo della modellazione parametrica e generativa, e si terrà da martedì 25.10.2016 a giovedì 27.10.2016 – dalle 10:00 alle 17:00.
Potete scaricare qui il PROGRAMMA DEL CORSO.
Il calendario dei corsi è consultabile qui.
VEGA Parco Scientifico TecnologicoVia della Libertà 12 – VeneziaEdificio Porta dell’Innovazione – Piano Terra
Per maggiori informazioni:
http://www.fablabvenezia.org/parametric-design-with-grasshopper/…
n en el diseño y fabricación digital de formas complejas y euclidianas.
Tomando como plataforma Grasshopper con RHINO, se explora y optimiza el diseño y fabricación de topologías complejas bajo los entornos de "Grasshopper", "RhinoNest" y "RhinoCAM" así como la parte de renderizado tipo high-end con Brazil.
D-O-F De 8:00 AM a 12:00 PM y de 1:00 PM a 5:00 PM
Contenidos:
1. Modelado Avanzado y sus Tecnicas. Aplanado y Desarrollo de Superficies.Anidado y distribución Nesting.
2. Introducción al Diseño Paramétrico.Definiciones Avanzadas de Grasshopper,posibilidades y limitaciones. Ajustes de escala para impresión y corte.
3. Introducción a la Manufactura en CNC - RhinoCAM 2.0.
4. Guía Paso a Paso para la realización de un Renderizado usando Brazil 2.0. Presentación DIGITAL de proyectos.
Docentes:
Andrés González - CEO McNeel Miami
Ovidio Cardona - Especialista en RhinoCAM y Zebra
Juan David Moreno - Especialista en Rhino y Brazil
Inversión:
$650 000 (Incluye licencia Educativa y Certificación de McNeel)
$550 000 ( Incluye Certificación de McNeel)
Informes:
Bits LTDA Tel: 412 30 15
Laboratorio de Imagen Facultad de Arquitectura Tel: 430 94 32…
ed according to list C.
I tried replace members, but it consists of geometry, so it doesn't worked.
In list C I filtered all the indices that need to be replaced.
All items in {0;0} from C need to be replaced by List B {0;0}
All items in {0;1} from C need to be replaced by List B {0;1}
And so on...
In the end everything needs to be fed into a orient component.
G is the geometry behind list B
A is the new list (but I don't know how to create)
B is the list A of all 60 panels
To wrap up the question:
I need to have entry 1 from list B in a new list on position: 0 1 2 3 5 6 7 10 11 12 15 16 21
I need to have entry 2 from list B in the same new list on position: 4 8 9 13 14 etc. etc. etc.
I wonder how I can do this :) Thanks in advance!
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