I assume that branch 0;0 has N = 10 points, 0;1 N = 7 points.
In the photo the way you describe the points it is like branch 0;0 has N = 45 points, where subbranch 0;0;1 has null points, subbrach 0;0;1 has N=1 point... subbranch 0;0;9 has N= 9 points.
Most likely you need to just graft you initial data tree that has the following structure
0;0 with N = 10
0;1 with N = 7
0;2 with N = 9
0;3 with N = 5
0;4 with N = 8
without a file, or a solid description of your starting data structure all these remain assumptions.
…
circles that can be populated (for each radius size) is set as an integer (or slider)
(ie. radius 1.5 = 10 , radius 3= 6, radius 6 = 6, radius 9=4)
Conditions are:
1) Each of the circle has a radius of influence,
Radius of influence = double the radius of the circle)
(3, 6, 12, 18)
2) Any overlapping circles in either: Radius of influence or the Circles are removed so that
No circles overlap.
3) There must also be 4 circles set at the corner points of the grid - These must be circles with a radius of 3 or 6
If you can do that I will be amazed as i've been trying for weeks! :(
Ive attached a sketch of what im looking for…
{0;1;0}N=6
{0;1;1}N=6
{0;1;2}N=5
{0;2;0}N=7
{0;2;1}N=8
{0;2;2}N=9
Can you shift and wrap any of the paths A B or C?
Say if I wanted to shift and wrap B by 1 to get the following...
{0;0;0}N=7
{0;0;1}N=8
{0;0;2}N=9
{0;1;0}N=3
{0;1;1}N=2
{0;1;2}N=5
{0;2;0}N=6
{0;2;1}N=6
{0;2;2}N=5…
0;0;1}
{5;0;1}
{9;0;1}
Applying a simplify operation would result in:
{0}
{5}
{9}
If we only had the first branch in each case they would be the same (to wit, {0;0;1}), what should it reduce to? You can only say which parts of a branch are redundant when you have something to compare it to.
--
David Rutten
david@mcneel.com
Tirol, Austria…
Hi,
in this moment I can't understand the table.
I have two list A and B both with 3 item, so I have 9 combinations. why the table has 4 column and not 3?
dn't get in the way.
I now have 9 spheres and 9 curves, properly aligned.
However, using the list of curves and surfaces in SrfSplit tries to split all 9 spheres with all 9 curves. I want to do a one-to-one matching (split sphere 1 with curve 1, sphere 2 with curve 2, etc). Is this possible?…