} (N=11) {0;1} (N=11) {0;2}(N = 11) {0;3}(N = 11) {0;4}(N = 11)
2. I run the Points that are coming out from the Divide Curve Components through the Path Mapper components with this definition:
{A;B} (i) > {A} (i)
3. I run data coming out from Path Mapper component through:
a) Parameter Viewer component and the result is:
{0} N=11 (data with 1 branches)
b) Point > Panel and the result is:
collection of 11 point (N=11) which is the exactly the same as the collection of point belonging to {0;4} (N = 11).
So, here is the question:
why the collection of points coming out from the Path Mapper {A;B} (i) > {A} (i) component is the same as the collection of points belonging to the curve {0;4}(N = 11) ?
Anyway ... It 's the first time I ask a question here... so I would like to thank you for what you do with your work! Thank you! You are really great!…
Writing simulation parameters...3. [2 of 8] No context surfaces...4. [3 of 8] Writing geometry...5. unsupported operand type(s) for +: 'str' and 'list'6. Failed to write Pelle_aperture000 to idf file7. unsupported operand type(s) for +: 'str' and 'list'8. Failed to write Pelle_aperture001 to idf file9. unsupported operand type(s) for +: 'str' and 'list'10. Failed to write Pelle_aperture002 to idf file11. [4 of 8] Writing Electric Load Center - Generator specifications ...12. [5 of 8] Writing materials and constructions...13. [6 of 8] Writing schedules...14. [7 of 8] Writing loads and ideal air system...15. [8 of 8] Writing outputs...16. ...... idf file is successfully written to : C:\Users\Personal\Desktop\TESI\x001\THOR\EnergyPlus\THOR.idf17. 18. Set runEnergyPlus to True!
or this
0. Current document units is in Meters1. Conversion to Meters will be applied = 1.0002. [1 of 8] Writing simulation parameters...3. [2 of 8] No context surfaces...4. [3 of 8] Writing geometry...5. Runtime error (MissingMemberException): 'hb_EPFenSurface' object has no attribute 'blindsMaterial'6. Traceback:line 1567, in main, "<string>"line 2134, in script
i think that i've same problem with my windows...any suggestion???
Thanks for all…
7 -18.2
8 5.02
9 12.4
10 18.1
11 7.01
12 5.11
13 2.35
this data is waveform data.
i want to pick out only climax(for example in upper data, number 1 and 10) from this data.
i have this problem...that is, i do not know to do what.
i think my English is strange...so you are difficult to understanding my question.…
hat position you would like in order:
1.
2.
3.
4.
5.
6.
7.
8.
9.
10.
11.
12.
You still must show up on time and you still must stay and work on your project during the duration of class.
See you all next week, I hope I won't still have this cough!
-Joseph Iwaskiw…
e
7. True
8. True <-- this one
9. True
10. False
11. True
12. False
13. True
14. True <-- this one
15. True
16. False
17. True
18. False
19. True
20. True <-- this one
21. True
22. False
23. True
24. False
25. True
26. True <-- this one
27. True
28. False
29. True
30. False
31. True
32. True <-- this one
33. True
Any idea how I can solve this?
Thanks!…
the catenary shape
6) Get the mid point of all the heaxgons
7) Create surfaces to get the average normal of each hexagons
8) Project the hexagon on the normal plane
9) Move the plane using the normals
10) create mesh faces between first and second hexagons
11) create mesh faces to close the planar hexagon
12) Orient all the mesh faces on a flat grid to laser cut them
13) Join and weld the mesh
14) Thicken the mesh using Weaverbird to get a shell
I hope this helps. It is all one mesh at the end made of quads on the side and triangles on the top (yes 6 of them).
All the best,
Arthur
…
could accomplish this by adding something like '5.0 + Slider * 3.0' into the expression field... (and having an integer slider with domain 0 to 6).
--
David Rutten
david@mcneel.com
Poprad, Slovakia…
Added by David Rutten at 10:19am on February 24, 2011
9 8 7 6
5 4 3 2 1 0
I am triangulating this surface. I want to select just the red vertices. As you can note, I just need the inner vertices of this surface. I could do it mannually, but if I want to change the mesh density later, I will have to pick all of them manually again later.
Can someone help me?
Tks
…
number of divisions on that curve as in the defintion (i.e. by 4). The offset in the def is slightly different and should cull two or three more curves as in the lists that show my aim below.
Basically I want to look into each branch of the groups of points from each closed curve . Marking in a list whether it contains a one or a zero (0= outside 1 = coincidents).
{0;0}0. 21. 22. 23. 2 {0;1} 0. 01. 22. 03. 2 {0;2}0. 01. 02. 03. 0 {0;3}0. 21. 22. 23. 2 {0;4}0. 21. 22. 23. 2 {0;5}0. 21. 22. 23. 2 {0;6}0. 01. 22. 23. 1 {0;7}0. 21. 22. 03. 0 {0;8}0. 21. 22. 23. 2 {0;9}0. 21. 22. 23. 2 {0;10}0. 21. 22. 23. 2 {0;11}0. 21. 22. 23. 2 {0;12}0. 21. 22. 23. 2 {0;13}0. 01. 22. 23. 0 {0;14}0. 21. 22. 23. 2
I want to create a list from these points. That marks each curve that pokes out, in a cull pattern as such:
20022210222202
Using a 1 where there are co-incidents in the curve points and the boundary. A 2 for true (outside points) and a 0 for containment. So I might be able to use the 1 in future developments - however if a true false list is easiest I can live with that.
So could I use F(x) function? - to look for 0 or 1's in each bunch of points and thus list as such for a cull pattern? or will Path mapper help me here? Or can I rely on simply grafting and splitting??
I am usure of the neatest solution and would love to learn. Hope you can direct me.rgrds
J.…
segments (ie. polylines)
2 = conic section (ie. arcs, circles, ellipses, parabolas, hyperbolas)
3 = standard freeform curve
5 = smoother freeform curve
The higher the degree, the less effect a single control-point has on the curve, but the further that weak effect reaches. Degree=5 curves are smoother, but it's also harder to add local details to it without adding a lot of control points. Rhino supports curves up to degree=11, but you almost never need more than 5.…