0;3} (N = 2)
{0;0;0;4} (N = 2)
{0;0;1;0} (N = 2)
{0;0;1;1} (N = 2)
{0;0;1;2} (N = 2)
{0;0;1;3} (N = 2)
{0;0;1;4} (N = 2)
Flattening this structure using the Flatten component would result in:
{0} (N = 20)
However, using a Path Mapper with the following masks will flatten is somewhat more intelligently:
{A;B;C;D} -> {A;B;C}
Now, you get:
{0;0;0} (N = 10)
{0;0;1} (N = 10)
--
David Rutten
david@mcneel.com
Poprad, Slovakia…
Added by David Rutten at 3:19am on December 14, 2009
Branch Address in the form {0;1;2;3;4;5;6;7;8;9;.......;N}
Try Grafting the input (I) Create Path by right clicking on it and selecting graft from the context menu…
Is it like this:
If a beam is connected from nod 0 to 1 and from 1 to 4. Another from 2 to 3 and from 3 to 5.
Node 1 and 3 have the same coordinates, but are they rigidly connected or not?
in the desired order.
0 = 0
1 = 1
2 = 6
3 = 7
4 = 8
5 = 9
6 = 12
7 = 13
8 = 2
9 = 3
10 = 4
11 = 5
12 = 10
13 = 11
Where the first number is the index and the second number is the actual sorting key. Then you sort these keys while sorting your curves in parallel using the A input of the Sort component.
--
David Rutten
david@mcneel.com
Poprad, Slovakia…