Search Results - 澳洲快乐8如何挣钱-『9TBH·COM』澳门大乐透49码--2023年3月19日6时46分34秒.H5c2a3.keyn8m8w9-gov-hk

Comment on: Topic 'Type_Codes': DateTime 9 = Guid 10 = string 20 = byte[] 21 = double[] 30 = System.Drawing.Point 31 = System.Drawing.PointF 32 = System.Drawing.Size 33 = System.Drawing.SizeF 34 = System.Drawing.Rectangle 35 = System.Drawing.RectangleF 36 = System.Drawing.Color 37 = System.Drawing.Bitmap 50 = GH_IO 2d point 51 = GH_IO 3d point 52 = GH_IO 4d point 60 = GH_IO 1d interval 61 = GH_IO 2d interval 70 = GH_IO line 71 = GH_IO bounding box 72 = GH_IO plane 80 = GH_IO version…; Added by David Rutten at 9:44am on November 15, 2017

Comment on: Video 'Parametric Design Study of Qatar Foundation Headquarters': 幅一般不超过全文的5%。摘要不需要具体阐述，不需要图表等也不需要评价。…; Added by naasaki at 2:00pm on May 12, 2021

Topic: How to divide a circle in segments of 2 different lengths: have 2 different lengths.Ex: 0, 2, 4 and 6 gets one length, while section 1, 3, 5 and 7 gets anotherAnyone here that has a good solution for this? Sincerely, Brage…; Added by Brage Hult at 4:22pm on July 24, 2015

Topic: list re-ordering: rve 10 curve 11 curve 12 curve 13 curve ...and I'd like to rearrange the order in which the curve are listed, to something like this: {0,0,0} 0 curve 1 curve 8 curve 9 curve 10 curve 11 curve 2 curve 3 curve 4 curve 5 curve 12 curve 13 curve 6 curve 7 curve I hope this makes sense. Thank in advance for any advice, John…; Added by John Fulton at 12:48pm on March 11, 2011

Topic: Curved parametric shed: fset the original curve in Z axis. 4) Offset my 3rd curve in the Y axis. 5) Divide al the curves into equal segments. 6) Use a cull pattern with "Tue False-False True" Booleans. 7) Connect the culled points. 8) Pipe around the curves. I dont´s know why my conections go from point 1 to point 2, and instead of keep going from point 2 to point 3, it starts back on point 3 to point 4. I´m sending the image of what I´m getting, the image of what I want to get, and the definition in case anyone can help me modifying some parameters or components. Thanks!…; Added by Federico Escobar Salas at 9:23am on November 27, 2009

Event: DIGITAL TOOLING vol.1: を進める。後半で行われるコンピュテーショナル・デザインの技術を使った料理の展開を紹介し、試食も行います。 ■第2部18:00～21:00（ワンドリンク制￥500） RGSS KANSAI(仮) 昨今、デザインの最先端で見られるようになったコンピューテーショナルデザイン。すでにスタジアムや大型建築、プロダクトデザインなどの分野で認知されてます。デザイナやデザイナを目指す人達には今後必須の技術と言えるのではないでしょうか。 RhinocerosとGrasshopperをつかえば、今までプログラムの知識が必要だったアルゴリズミックな3Dデザインもスクリプティングを要さず生み出すことができます。首都圏では数年前からRGSS（コンピューテーショナルデザインのコミュニティ）が存在し日本におけるコンピューテーショナルデザインの裾野を拡げています。コンピューテーショナルデザインに関する技術や知識の交流が発生し、関西におけるデザイン技術の底上げを期待しています。当日は2~3名のプレゼンテーションを予定。まずはキックオフ的にはじめてみて、続けていくことで形作っていければと思います。　大前道久　OPH（おっさんパワーハウス）主催　15年間ジュエリーメーカーで勤務し、　制作からデザインまで様々な部署を経験してきました。　Grasshopperの恩恵を受け、新しい表現や効率的な　モデリングを実践しています。　私なりの、コンピューテーショナルなジュエリー制作を　見ていただきたいと思います。 FBイベントページ：https://www.facebook.com/events/709226442478364/…; Added by Michihisa Omae at 9:09pm on August 23, 2014

Topic: List dispatching to multiple streams in non regular pattern: e a list of coordinates which I need to sort in groups as per a series of numbers in another list. Both are txt files which I'm reading to bring a series of points in but those points are generated with a corresponding index. Of course the lists are not sorted in any way, but the numbers are corresponding so it looks like a series of 9, 6, 7, 2, 8, 0, 9, 5, 6, 4, 2, 3, 8, 5, 5, 6, 9, 4 in one file( and series of (X, Y, Z) coordinates in the other. The question is how can I make it to sort the list and then split it per index... if it is possible... or should I just do this in excel and bring clean lists in? My idea, if it works, is use the series of points to generate paths and work with them. I'll attach the lists just if it helps making a clear idea. Any advice will be very welcome.…; Added by Arturo Steinberg at 12:25am on May 28, 2012

Comment on: Topic 'recursion in c#': n; n = (int) (Math.Log10((double) nfaces / 20.0) / Math.Log10(4.0)); double t = (1.0 + Math.Sqrt(5.0)) / 2.0; double c = Math.Sqrt(1 + (1.0 + Math.Sqrt(5.0)) * (1.0 + Math.Sqrt(5.0)) / 4.0); //Icosaedron Rhino.Geometry.Mesh mesh = new Rhino.Geometry.Mesh(); mesh.Vertices.Add(-1 / c, t / c, 0); mesh.Vertices.Add(1 / c, t / c, 0); mesh.Vertices.Add(-1 / c, -t / c, 0); mesh.Vertices.Add(1 / c, -t / c, 0); mesh.Vertices.Add(0, -1 / c, t / c); mesh.Vertices.Add(0, 1 / c, t / c); mesh.Vertices.Add(0, -1 / c, -t / c); mesh.Vertices.Add(0, 1 / c, -t / c); mesh.Vertices.Add(t / c, 0, -1 / c); mesh.Vertices.Add(t / c, 0, 1 / c); mesh.Vertices.Add(-t / c, 0, -1 / c); mesh.Vertices.Add(-t / c, 0, 1 / c); mesh.Faces.AddFace(0, 11, 5); mesh.Faces.AddFace(0, 5, 1); mesh.Faces.AddFace(0, 1, 7); mesh.Faces.AddFace(0, 7, 10); mesh.Faces.AddFace(0, 10, 11); mesh.Faces.AddFace(1, 5, 9); mesh.Faces.AddFace(5, 11, 4); mesh.Faces.AddFace(11, 10, 2); mesh.Faces.AddFace(10, 7, 6); mesh.Faces.AddFace(7, 1, 8); // 5 faces around point 3 mesh.Faces.AddFace(3, 9, 4); mesh.Faces.AddFace(3, 4, 2); mesh.Faces.AddFace(3, 2, 6); mesh.Faces.AddFace(3, 6, 8); mesh.Faces.AddFace(3, 8, 9); // 5 adjacent faces mesh.Faces.AddFace(4, 9, 5); mesh.Faces.AddFace(2, 4, 11); mesh.Faces.AddFace(6, 2, 10); mesh.Faces.AddFace(8, 6, 7); mesh.Faces.AddFace(9, 8, 1); for (int i = 0; i < n; i++) { Rhino.Geometry.Mesh mesh_rec = new Rhino.Geometry.Mesh(); recursiveSubdivision(mesh, ref mesh_rec); mesh = mesh_rec; } mesh.Vertices.CombineIdentical(true, true); mesh.Normals.ComputeNormals(); mesh.Compact(); A = mesh; } // <Custom additional code> public void recursiveSubdivision(Mesh mesh, ref Mesh mesh_rec) { int ind = 0; for (int i = 0; i < mesh.Faces.Count; i++) { Point3f A = new Point3f(mesh.Vertices[mesh.Faces[i].A].X, mesh.Vertices[mesh.Faces[i].A].Y, mesh.Vertices[mesh.Faces[i].A].Z); Point3f B = new Point3f(mesh.Vertices[mesh.Faces[i].B].X, mesh.Vertices[mesh.Faces[i].B].Y, mesh.Vertices[mesh.Faces[i].B].Z); Point3f C = new Point3f(mesh.Vertices[mesh.Faces[i].C].X, mesh.Vertices[mesh.Faces[i].C].Y, mesh.Vertices[mesh.Faces[i].C].Z); ind = mesh_rec.Vertices.Count; mesh_rec.Vertices.Add(A);//0 mesh_rec.Vertices.Add(middle(A, B)); mesh_rec.Vertices.Add(B); mesh_rec.Vertices.Add(middle(B, C)); mesh_rec.Vertices.Add(C); mesh_rec.Vertices.Add(middle(C, A)); mesh_rec.Faces.AddFace(ind + 0, ind + 1, ind + 5); mesh_rec.Faces.AddFace(ind + 1, ind + 3, ind + 5); mesh_rec.Faces.AddFace(ind + 1, ind + 2, ind + 3); mesh_rec.Faces.AddFace(ind + 5, ind + 3, ind + 4); } } public Point3f middle(Point3f A, Point3f B) { Point3f AB = new Point3f(); float length; AB.X = (A.X + B.X) / 2; AB.Y = (A.Y + B.Y) / 2; AB.Z = (A.Z + B.Z) / 2; length = (float) Math.Sqrt(AB.X * AB.X + AB.Y * AB.Y + AB.Z * AB.Z); AB.X = AB.X / length; AB.Y = AB.Y / length; AB.Z = AB.Z / length; return AB; }…; Added by Laurent DELRIEU at 12:58pm on August 6, 2016

Comment on: Topic '"Shatter" segments at their intersection points': Also, there is a problem with ignoring curves which don't intersect anything. Fast fix attached, but would need more work to make it really clean.…; Added by Yoann Mescam (Systemiq) at 5:16pm on May 13, 2016

Topic: Brep / Plane Intersection output order: a longer approach based on Brep / Plane intersection because the Brep / Brep or Region Intersection only works if the surfaces cross. To find the unique cases in which the surfaces intersect, I am using the [Cross Reference] set at diagonal and culling the surfaces that are coplanar. The problem comes when I wan't to relate the given intersection, with the corresponding surface. I think, the intersections should be four and at paths: 8, 17, 19, 29. But there are 8 intersections, and more importantly I have no idea why gh is outputting those paths. …; Added by Jesus Galvez at 9:03am on April 26, 2013