number of divisions on that curve as in the defintion (i.e. by 4). The offset in the def is slightly different and should cull two or three more curves as in the lists that show my aim below.
Basically I want to look into each branch of the groups of points from each closed curve . Marking in a list whether it contains a one or a zero (0= outside 1 = coincidents).
{0;0}0. 21. 22. 23. 2 {0;1} 0. 01. 22. 03. 2 {0;2}0. 01. 02. 03. 0 {0;3}0. 21. 22. 23. 2 {0;4}0. 21. 22. 23. 2 {0;5}0. 21. 22. 23. 2 {0;6}0. 01. 22. 23. 1 {0;7}0. 21. 22. 03. 0 {0;8}0. 21. 22. 23. 2 {0;9}0. 21. 22. 23. 2 {0;10}0. 21. 22. 23. 2 {0;11}0. 21. 22. 23. 2 {0;12}0. 21. 22. 23. 2 {0;13}0. 01. 22. 23. 0 {0;14}0. 21. 22. 23. 2
I want to create a list from these points. That marks each curve that pokes out, in a cull pattern as such:
20022210222202
Using a 1 where there are co-incidents in the curve points and the boundary. A 2 for true (outside points) and a 0 for containment. So I might be able to use the 1 in future developments - however if a true false list is easiest I can live with that.
So could I use F(x) function? - to look for 0 or 1's in each bunch of points and thus list as such for a cull pattern? or will Path mapper help me here? Or can I rely on simply grafting and splitting??
I am usure of the neatest solution and would love to learn. Hope you can direct me.rgrds
J.…
rve
10 curve
11 curve
12 curve
13 curve
...and I'd like to rearrange the order in which the curve are listed, to something like this:
{0,0,0}
0 curve
1 curve
8 curve
9 curve
10 curve
11 curve
2 curve
3 curve
4 curve
5 curve
12 curve
13 curve
6 curve
7 curve
I hope this makes sense.
Thank in advance for any advice,
John…
vector * number
8. number * point
9. point * number
10. complex * complex
11. colour * colour
12. colour * number
13. number * colour
--
David Rutten
david@mcneel.com
Seattle, WA…
Added by David Rutten at 10:39pm on November 12, 2010
) function if you've already got a boolean value.
This expression:
x < 12
results in exactly the same things as this expression:
If( x < 12, True, False )
If() is only really useful when you want to return non-boolean data, like so:
If( x < 12, x, 100-x )
In this case, the expression will return either x, or 100-x if x is larger than or equal to 12:
x result
1 1
2 2
10 10
11 11
12 88
13 87
14 86
18 82
70 30
--
David Rutten
david@mcneel.com
Poprad, Slovakia…
Added by David Rutten at 7:22am on August 10, 2011
)
3. KeyError(1417,)
4. KeyError(1417,)
5. KeyError(1417,)
6. KeyError(1417,)
7. KeyError(1417,)
8. KeyError(1417,)
9. KeyError(1417,)
10. KeyError(1417,)
11.......
i tried different weather file but also same result. it seems i have same problem. the file am working on is the radiation file i took from the examples . whats seems to be the problem?
thank you for your time…
Writing simulation parameters...3. [2 of 8] No context surfaces...4. [3 of 8] Writing geometry...5. unsupported operand type(s) for +: 'str' and 'list'6. Failed to write Pelle_aperture000 to idf file7. unsupported operand type(s) for +: 'str' and 'list'8. Failed to write Pelle_aperture001 to idf file9. unsupported operand type(s) for +: 'str' and 'list'10. Failed to write Pelle_aperture002 to idf file11. [4 of 8] Writing Electric Load Center - Generator specifications ...12. [5 of 8] Writing materials and constructions...13. [6 of 8] Writing schedules...14. [7 of 8] Writing loads and ideal air system...15. [8 of 8] Writing outputs...16. ...... idf file is successfully written to : C:\Users\Personal\Desktop\TESI\x001\THOR\EnergyPlus\THOR.idf17. 18. Set runEnergyPlus to True!
or this
0. Current document units is in Meters1. Conversion to Meters will be applied = 1.0002. [1 of 8] Writing simulation parameters...3. [2 of 8] No context surfaces...4. [3 of 8] Writing geometry...5. Runtime error (MissingMemberException): 'hb_EPFenSurface' object has no attribute 'blindsMaterial'6. Traceback:line 1567, in main, "<string>"line 2134, in script
i think that i've same problem with my windows...any suggestion???
Thanks for all…
0 to x14 and high from y0 to y24 , on the plane you set.
(The "Rectangle" component wants a plane in "P", and because you connected the center point of the previous rectangle, it automatically convert that point to a new XY(world) plane with origin on that point)
You have to work like this then:
X= -5.5 to +5.5 (on the new centered plane)
Y= -12 to +12 (on the new centered plane)
…