inds 3 points closer than the threshold and 3 furhter
3. It forms 3 groups containing 3 points each + 3 separate groups containing 1 point each
Is that correct?
Also, how to extract one of the group? I wanted to use Tree Item and write number of the group in index but I don't know what "path" is for.
Thanks in advance for answer,
PS: Can I ask anyone for a very simple example in gh of how this component works and showing how to extract one of the groups?…
s 8, 4, 2, 10, 1, 3, 8, 4, 2, 0. But then for the end result to maintain all numbers above 5 but replace all numbers below with a defined number..Let's say zero. So then the list would read...8, 0, 0, 10, 0, 0, 8, 0, 0.…
o now is select and group together list items by their index. {0:0} and {2:0} also {1:0} and {3:0}. They way I'm doing this at the moment is quite complicated and I'm sure there's an easier way to achieve the same result.
maybe someone in here knows a solution?
thanks a lot…
;1},{0;2},{0;3}, (note that the first item is NOT {0,0})
{1;1}{1;2},{1;3},
{2;1},{2;2},{2;3},
{3;1}{3;2},{3;3}...
Well I'll just upload an extract of the definition. The data path should be the same, but with the items in the last path shifted to the first path, and the items in the first path shifted to the second path and so on.
I'll keep trying. …
{4}-0;3
{5}-6;7
{6}-5;7
{7}-5;6
Here it can be shown that there are two subgraphs containing 0,1,2,3,4 and 5,6,7. How can I use spiderweb (either using scripting or the components) to give me this result when I have many more vertices??
Thanks,
Sam…
0;3} - 2 curves
{1;1} - 2 curves
{1;2} - 2 curves
{1;3} - 2 curves
{1;1} - 2 curves
{2;2} - 2 curves
{2;3}- 2 curves
And what I want.
{0} - 6 curves
{1} - 8 curves
{2} - 4 curves
I have tried some different stuff whit the path mapper tool, but I am not to skilled in using it. I imagine it can do the work for me?.
If anyone can help me out, I would be glad.
…