should not be open).
3. All releases of Rhino 5, Arduino, GH, and FF are the latest as of May 21st.
I Boolean toggled the port open, but I can't seem to get any output to display from the UnoRead component. I was hoping to see values from any of the analog inputs (APin5 depicted) connected as info gets sent back and forth between the Arduino and my comp. I'm getting simultaneous "Hooray" and "Whoops" messages, and I can't pinpoint why. See attached JPG.
Does it have to do with the fact that I have a list of COM ports? Even though I know COM 3 is the correct one as defined in the IDE, do I need to re-declare it in Grasshopper as well? Does the {0} shown impact this output?
Any direction is appreciated.
Thanks - JFig
…
Here it the RhinoScript that I am using:
'Option Explicit
'Rem Script written by Giulio
'Rem Script version lunes, 10 de noviembre de 2008 21:00:00
'Rem This script is licenced to you under the conditions shown at
'Rem http://www.giuliopiacentino.com/this/
Call Main()
Sub Main()'starts command
Dim arrLfStart(),arrRxStart(), arrLfEnd(), arrRxEnd(), arrLinks(), i 'sets intergers
Dim links: links = 36 'number of cylinders (links)
ReDim arrLfStart(links), arrRxStart(links), arrLfEnd(links), arrRxEnd(links), arrLinks(links) 'combines integer with number
Dim angleDist:angleDist = Rhino.PI / 10
For i=0 To links 'sets integer
'The following sets the path
arrLfStart(i) = Array(Cos(i-angleDist)*3 + Cos(i*12)*12, Sin(i-angleDist)*3 + Sin(i*12)*12, i*5)
arrRxStart(i) = Array(Cos(i+angleDist)*3 + Cos(i*12)*12, Sin(i+angleDist)*3 + Sin(i*12)*12, i*5)
arrLfEnd(i) = Array(-Cos(i-angleDist)*3 + Cos(i*12)*12, -Sin(i-angleDist)*3 + Sin(i*12)*12, i*5)
arrRxEnd(i) = Array(-Cos(i+angleDist)*3 + Cos(i*12)*12, -Sin(i+angleDist)*3 + Sin(i*12)*12, i*5)
'The following adds cylindars according to specified points
Call Rhino.AddCylinder(IntraPts(arrLfStart(i), arrRxStart(i), 0.5), IntraPts(arrLfEnd(i), arrRxEnd(i), 0.5), 0.5)
Next
'The following adds surfaces to the path
Call Rhino.AddLoftSrf(Array(Rhino.AddInterpCurve(arrLfStart), Rhino.AddInterpCurve(arrRxStart)))
Call Rhino.AddLoftSrf(Array(Rhino.AddInterpCurve(arrLfEnd), Rhino.AddInterpCurve(arrRxEnd)))
End Sub
Function IntraPts(byRef p1, byRef p2,byRef n)
'Rem This function gives the first point out if you use n=0,
'Rem with n=1 it gives the second point.
IntraPts = Array( p1(0)*(1.0-n)+p2(0)*n, p1(1)*(1.0-n)+p2(1)*n, p1(2)*(1.0-n)+p2(2)*n )
End Function
I know that the script works in RhinoScript. If anyone could help me out I would appreciate it.…
Added by Adam Smith at 1:57pm on September 9, 2010
53 → 53 → 63 → 74 → 74 → 84 → 9
As you can see from the above list the connection sequence comes in waves of three, where each group of similar indices on the left is associated with a group of three incrementing indices on the right.
Some combination of Series components will probably generate this list, but it'll only work for the first ring, the second one will need a different connection pattern. It is perhaps better to just encode the integer pairs by hand. But then you cannot change your mind about the number of sides later.…
Added by David Rutten at 10:39am on October 21, 2015
The best way is to use a C# or a VB component to transpose these
lists. I think in C# you can use transpose directly. You can ask this
on the VB/C# forum on our new website, www.grasshopper3d.com
- Scott
On May 27, 3:56 am, Tonsgaard wrote:
> Being a long time user of Generative Components trying to use
> grasshopper i miss the "transpose" command.
> I have a point list like this:
>
> 0, 1, 2, 3, 4, 5
> 0, 1, 2, 3, 4, 5
> 0, 1, 2, 3, 4, 5
> 0, 1, 2, 3, 4, 5
> 0, 1, 2, 3, 4, 5
>
> and a want to transpose dimensions to:
>
> 1, 1, 1, 1, 1
> 2, 2, 2, 2, 2
> 3, 3, 3, 3, 3
> 4, 4, 4, 4, 4
> 5, 5, 5, 5, 5
>
> Surely I am not the first in need of this...
> how would i go about and do this...? I suppose its quite easy in VB
> script, but being used to GC's C# like language, I kinda dont know how
> to do this...
>
> thanks...
>
> Tonsgaard…
en 3 of them, and one poolyline between two of them.
It would also be very nice if i could control it so that only the successive ones can be connected
so if {0:0:0} has 8 points and {0:0:1} has 8, as do {0:0:5} and {0:0:6} i would like to have this as two polylines, not one continoous that would in this case jump three branches (or curves that are shorter).
Does this make any sense?…
Added by Dusan Bosnjak at 2:08pm on September 28, 2009
a.m to 7 p.m of everyday from June 5th to July 9th), and a certain time during a long period (ex. 12 a.m of every day on June)?
Thank you in advance.
Bi Xiaojian…
indexes later and the k value is just 5. The goal is to output all combinations of length 5 from the list of integers 0 to 19.
I placed the list in brackets in order to make it iterable (I don't really know what this means.) Somehow I need to get the combinations out of the itertools.combination output.…