middle index, and choose that point with List Item. If even, for example 4 points (0, 1, 2, 3), you'll get 2, so subtract one and choose those two indices, 1 and 2. I only had a few minutes to play with this, so it isn't a fully-baked solution, but it should take you a little further.…
starts at 1 not 0 by default. (S=1)
The results are you want to shift the curves by 1, 2, 3 and 4 whilst the wrapping flag remains on False therefore shortening the list.…
for instance
if i have a bunch of pionts, say "4", i want the connection of them without getting connections within the same 2 points.
the answer should be (4X3) / (1X2).
Is it like this:
If a beam is connected from nod 0 to 1 and from 1 to 4. Another from 2 to 3 and from 3 to 5.
Node 1 and 3 have the same coordinates, but are they rigidly connected or not?