{4}-0;3
{5}-6;7
{6}-5;7
{7}-5;6
Here it can be shown that there are two subgraphs containing 0,1,2,3,4 and 5,6,7. How can I use spiderweb (either using scripting or the components) to give me this result when I have many more vertices??
Thanks,
Sam…
vector * number
8. number * point
9. point * number
10. complex * complex
11. colour * colour
12. colour * number
13. number * colour
--
David Rutten
david@mcneel.com
Seattle, WA…
Added by David Rutten at 10:39pm on November 12, 2010
m And the resulting Tangent Arc Length is 20.95 mI wonder if anyone could help me with thisHow do you round off the Tangent Arc Length to a whole number by creating a Loop to adjust or to fine tune the initial setting 1, 2, and 3. (1, 2, and 3 doesn't necessary to be a whole numberI try to connect Galapagos genome without knowing how to connect the fitness output to. Any one with ideas?…
g definition but in diva for grasshopper in material it just appear dusty_med and not metal_railings and metal_treads. How I should write the correct definition?
void brightfunc dusty_med4 dirt dirt.cal -s 101 .25
dusty_med metal metal_railings005 .7 .7 .7 .3 .2
dusty_med metal metal_treads005 .5 .5 .5 .3 .2…
our example file you use key name (such as my : MyEquation )
then you use Equation > (x^2 + (9*y^2)/4 + z^2 - 1)^3 - x^2*z^3 -((9*(y^2)*(z^3))/80)
where do you find all those goodies ?? all those expressions and equations
thnx…
Added by AJ to Volvox at 4:28am on August 22, 2017
ant to find all paths where exactly two items are the same like in branch {1}. How can I solve this in VB? Is there an easy "search in list" class or do I have to iterate over all items by myself ??
Regards Alex…
ap value = True
Shift List = 1 --> (B,C,D,A)
Shift List = 2 --> (C,D,A,B)
You can also use negative values.
Shift List = -1 --> (A,B,C)
Shift List = -2 --> (A,B)
and with Wrap = True
Shift List = -1 --> (D,A,B,C)
Shift List = -2 --> (C,D,A,B)
The most useful Shift List action I use is to either get rid of the first or last item in a list and sometimes both.
Shift list = -1 --> (A,B,C) Shift list = 1 --> (B,C)
In the example posted above you are creating a shift list value equal to its location along the curve. The first section = 0 doesn't get shifted, the second section gets a shift = 1, third = 2, forth = 3 and because the wrap value is set to true the fifth section gets back to 0, sixth = 1 etc etc. creating the twisting effect.
The "one more stupid question" answer is Mass Addition. You will find the component on the Math tab or you can type it into the Keyword search feature (by double clicking the canvas). This component has two outputs a total amount for each list and a partial set of results giving:
List (3,6,9,12)
{0} = 3
{1} = 3+6 = 9
{2} = 3+6+9 = 18
{3} = 3+6+9+12 = 30…
Let's say first curve is divided by 1, the second one by 3, the third one by 9, then by 27 and etc. I tried to raise (i+start) to the power of 3: 3**(i+start). It kinda worked, but not sure if it's the correct way.…