TREE B
{0} n=1 {0;1} n=4
{1} n=1 {0;4} n=4
{2} n=1 {1;1} n=4
{1;2} n=4
{1;3} n=4
{1;4} n=4
{2;1} n=2
{2;2} n=4
{2;3} n=4
{2;4} n=4
Both trees are generated from sliders, so could have any number of branches, although they are tied together. Tree A is a set of division points on a line, Tree B is a set of intersections from lines generated radially from the first (in this case three) points. I am trying to perform a "closest point" operation between the first tree and the second tree-- only, I do not want them to cross list, or long or short list. I want the {0} point to operate with those entries in the 2nd tree that start with {0,x}. So it would look like
{0} --> closest point with {0;1},{0;4}
{1} --> closest point with {1;1},{1,2},{1,3},{1,4} etc
I cannot figure out how this works. What I am visually trying to do is cast rays from a string of points so that they stop when they encounter another curve. I am having trouble picking through the intersection events to get what I want. Check the attached files for some clarity. THANK YOU…
Added by Joshua Jordan at 12:06am on February 5, 2012
one list by -1 while disabling index wrapping. Essentially, this removes the first item from one list and the last item from the other list. Conceptually, these are your lists:
Source List: [0, 1, 2, 3, 4, 5]
Shift List 1: [0, 1, 2, 3, 4]
Shift List 2: [1, 2, 3, 4, 5]
If you input these lists into a Line component, you will connect each respective list item with the other, essentially 0-1, 1-2, 2-3, etc.
…
、、、不同角度的理解、诠释、运用和发掘规律、、、
新闻或者幻觉:马王堆墓穴中发掘出了丝绸做的鞋,不算是现代意义上真正的鞋,但是完成了一个完整的公式。
有一部分需要是共同的,在离开了沙滩和草地的时候。
找一个成熟的不一样的数学思维合作者,(可以一起申请参加sg2014活动,也可以不)
我想听到人们写给自己的语言,我不害怕听不懂;
也不在意你能看到我的美丽的脚和我们美丽的城市。
你存在?存在0.1%?如果≥1/4
With the two version of the PDF in the file upload, doubt, 10th should be able to see the many PDF.
There are some scruples, confusion ——"The additional property of professional activities",——Subject classification, commercial, regional、、、
There is a place Africa, people don't wear shoes, A few people with grass or leather on the foot (and buildings——In order to spatial density) winding,
the manufacture of shoes, two sales do two judgment:
A There is no life belongs to shoes
B this is the market.
I spent a lot of energy explained to students, which is not to do programming people do、、、 the different angle understanding, interpretation, application and explore the law、、、
The news or illusion:Mawangdui tomb unearthed silk shoes , is not the modern sense of true shoes, but the completion of a complete formula.
There is a need is common, when they leave the beach and grass.
Find a mathematically mature different thinking partners,(Can apply to participate in the activities of the sg2014, also can not)
I want to hear people wrote their own language, I am not afraid of don't understand;
Don't care what you can see my beautiful feet and our beautiful city.
Do you have? There are 0.1%? If ≥1 / 4 You know what I did wheni found out about you?
msxf6688@163.com
…
a seed, and instead creating a pattern where each color has a seed/control slider for each row? For example, row 1: brown 2, tan 6, yellow 7, purple 3, repeat. row 2: brown 6, tan 1, yellow 4, purple 10, repeat. row 3: yellow 5, purple 1, brown 3, tan 10, repeat. row 4: purple 2, brown 7, tan 3, yellow 4, repeat. Then repeat that sequence up the wall? For each color, the number in the sequence should be adjustable.
Thank you again for your help!…
4}
{0;2;0}
{0;2;1}
{0;2;2}
{0;2;3}
{0;2;4}
You cannot flip this because this is more complex than a rectangular matrix. You're going to have to do the mapping yourself. Try a Path Mapper with the following masks:
{A;B;C}(i) -> {A;B;i}(C)
Which should give you a structure that results in 3 lofts.
--
David Rutten
david@mcneel.com
Poprad, Slovakia
…
Added by David Rutten at 3:18pm on November 27, 2011