simplified in the bake name attribute and on the bake object component. I was counting on maintaining that structure.
{0;4}
{0;4}
{1;2}
{1;2}
Easily fixed with an additional attribute. Just curious on the behavior. Thanks.
…
Added by japhy to EleFront at 3:18pm on October 9, 2017
13 5 15 6 17 7 ... …
But it seems I have not been clear:
the input values (3,5,7,9,11,13) should be presented in the way of "number slider" parameter. So by increasing the value of the slider from minimum 3, to 5, 7, 9, 13, 15, 17... I should get an output numbers of 0,1,3,4,5,6,7...
So I if choose value 3 on the input "number slider", on the other end, I want 0 as an output.
Or if I choose value 5 on the input "number slider", I want 1 as an output, and so on.
Is this possible?…
vas
Closing and creating a new file (memory resets when this is done) @4:00, 5:57, 6:53
System slow down and crashes @ 8:16 (takes 5 minutes to end the process - perhaps not the most entertaining movie to watch until the end - a good point to turn the kettle on)…
up, 6 in the sixth group through the 31st group, 4 in the 32nd group, 2 in the 33rd group.
Side note to David... Since data matching is such a key aspect as definitions become more sophisticated it seems like there should be a much, more comprehensive and intuitive methods to manipulate tree structures. …
Added by Stan Carroll at 12:43pm on April 14, 2011
That is correct. In reality there are 3 major versions of .NET 1, 2, and 4 (different versions of mscorlib.dll)
Rhino 4 uses .NET 2 which includes 3 and 3.5.
Rhino 5 uses .NET 4
dimension of matrices must be identical) and division is the same as multiplication (dimension must be in the order of A(mxn)*\/B(nxk) where n is the common dimension): to divide one element by another you just multiply it by 1/value (part or all of the elements can multiply while part or all of the elements divide):
so for example matrix addition of matrices A(2x2): {2,-1}{1,2} and B(2,2): {3,-5}{4,-2} will result in matrix C(2x2):{5,-6}{5,0}. subtraction of those matrices will result in D(2x2): {-1,4}{-3,4}
Division of matrices A(2x2): {2,0.5}{2,4} and B(2x1) :{2}{2} will result in matrix C(2x1): {1+0.25}{1+2}={1.25,3}. Multiplication of those matrices will result in D(2x1):{4+1}{4+8}={5,12}.…
i mean, i want a slider that can do 3 sides, 4 sides, 5, 6, 7, 8, 9 and 10. for the grids because I dont want to use a fixed grid shape such as square grid (4 sides only).