s points"
(the set didnt change from the picture above)
so param viewers show me (with 3 columns points)
1 list with 3 branches : {0;0}/{0;1}/{0;2}
an other with 4 branches : {0;0;0}/{0;0;1}/{0;0;2}/{0;0;3}
I tried to merge those 2 and then input the list in a path mapper but could'nt manage to make it work to get :
{0;0;0}/{0;0}/{0;0;1}/{0;1}/{0;0;2}/{0;2}/{0;0;3}
Am I using the right component?…
;1},{0;2},{0;3}, (note that the first item is NOT {0,0})
{1;1}{1;2},{1;3},
{2;1},{2;2},{2;3},
{3;1}{3;2},{3;3}...
Well I'll just upload an extract of the definition. The data path should be the same, but with the items in the last path shifted to the first path, and the items in the first path shifted to the second path and so on.
I'll keep trying. …
t item (see the image), is it possible to do this in another way (quickly) ?
Is it possible to divide that curve into 2 separate curves using a point that i've used for the division?
Thanks…
Added by luca.pavarin at 4:08pm on January 7, 2010
eep track of the path names yourself.
You can use the Replace Branches component to rename.
For instance:
(Paths = 2)
{0;1}
{0;2}
and
(Paths = 3)
{0;1} rename {0;3}
{0;2} rename {0;4}
{0;3} rename {0;5}
Does this make enough sense to get you started?
-taz…
13;2} ... 20.{13;12}
21. {21;0}22. {21;1}23. {21;2} ... 41. {21;20}
42. {34;0}43. {34;1}44. {34;2} ... 75. {34;33}
76. {55;0}77. {55;1} ... ....
I want to grab the first 8 [0-7], the next 13[8-20], the next 21[21-42] etc
so i have the (known fibonacci seq) list of numbers on the left here:
C S
8 0
13 8
21 21
34 42
55 76
89 131
144 220
233 364
and i need the list on the right, so that i can select items using a Series (N=1 and S and C from the list above) and a List Item component.
the simple question is:
is there a component that can take a list and accumulate it in this way that I need?
if not, is there anyone that can point me to a simple relevant VB example so i could easily adapt it?
many thanks,
gotjosh…
o three parts:
branch 1:
{0;0} N = 3
{0;1} N = 3
branch 2:
{1;0} N = 5
{1;1} N = 5
branch 3:
{2;0} N = 30
{2;1} N = 30
parthmapper won't change the length of branch, explode tree won't give me two branches in one output
…