rated by "<" symbols. Examples: "2<10", "2<4<10", "Pow(2, 1)<5*Sin(3)<10".
The entered text contains 2 or 3 segments separated by two or more consecutive dots. Examples "2..10", "2..4..10", "Pow(2, 1)....5*Sin(3)..10".
If only two segments are provided, then the initial value will be the same as the minimum value. If a bounds number or a default value is written as a simple number, then the number of decimal places will be harvested. I.e. "2..4..10" is not the same as "2..4..10.00" as the former will result in an integer slider and the latter in a slider with two decimal places.
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David Rutten
david@mcneel.com
Poprad, Slovakia…
Added by David Rutten at 10:08am on February 15, 2013
the curves on surface issue it's solved seting flatten to the surface control point output. Still didnt know how to group points like:
1;1, 2;2, 3;3.....
1;2, 2;3, 3;4....
1;3, 2;4, 3;5...
....
hink you need recursion to modify the random seed; many other ways to accomplish that (use the length of each curve as the seed, for example).
Using multiples of twelve makes it harder for me to grasp the essence of the matter; another way of looking at it is that you want to generate random integers from 2 to 5 (24,36, 48 and 60) and have them add up exactly to curve lengths of 5 (x12=60), 9 (x12=108) or 14 (x12=168).
So you want to generate random numbers until their sum ('Mass Addition') plus 5 is equal to or greater than the curve length (5, 9 or 14). The last number in the series is then not random but just the difference between the two.
For example, for curve length = 5 (x12=60), there are only three possible numbers that can be used as the first in the sequence: 2, 3 or 5. If it's 5, you're done. If it's 2, the second number is 3 (5-2), if it's 3, the second number is 2 (5 - 3). You can't use '4' at all because the remainder, 1 (x12=12) isn't one of your solution options.
There is no point in generating the last number randomly, eh?
P.S. You didn't use 'Internalize data' for the 'Curve (Crv)' param in your GH file.…
Added by Joseph Oster at 2:29pm on September 12, 2015
work. If you have been looking for an opportunity to get into a new part of the software or just want to get updated on the latest developments in a 90-minute presentation, then these webinars are for you. Starting this Thursday at 12:30 EST, the workshops will begin by covering basic Ladybug capabilities and will provide a survey of the latest community resources. Each Thursday, there will be another presentation covering progressively advanced topics. In total there will be 5 workshops, each of which you can register for by clicking below:
1 - Ladybug Climate Analysis - August 25th, 12:30 PM EST2 - Ladybug Facade + Shade Design - September 1st, 12:30 PM EST3 - Honeybee Energy, HVAC + Indoor Comfort Modeling - September 8th, 12:30 PM EST4 - Honeybee Daylight + Electric Light - September 15th, 12:30 PM EST5 - Honeybee THERM + WINDOW - September 22nd, 12:30 PM EST
Notably, workshops 2, 3, 4 and 5 will feature substantial coverage of capabilities that do not currently have tutorial videos. This includes new view analysis and tips and tricks for radiation studies in webinar 2, newly-released HVAC capabilities for webinar 3, electric lighting capabilities with webinar 4, and all of webinar 5 will be brand-new hot-off-the-press development! Hope that you can attend!…
This must be a bug because its true for dividing by all odd numbers:
(i-1)/3
(i-2)/5
(i-3)/7
(i-4)/9
(i-5)/11
....
(i-n)/2n+1
And you can't make it work for even numbers
Added by Danny Boyes at 5:06pm on January 13, 2010
nts me this:
[[0], [0, 1], [0, 1, 2], [0, 1, 2, 3], [0, 1, 2, 3, 4], [0, 1, 2, 3, 4, 5], [0, 1, 2, 3, 4, 5, 6], [0, 1, 2, 3, 4, 5, 6, 7]]
this is what I wanted but how to convert this to tree in grasshopper?
In grasshopper I just get:
8x IronPython.Runtime.List…
branches in each A's list of B's, or remove its ends etcso that if I want to remove the last B in every A{0;1},{0;2},{0;3},{0;4},{0;5},{0;6}{1;1},{1;2},{1;3},{1;4}{2;1},{2;2},{2;3},{2;4},{2;5}would become{0;1},{0;2},{0;3},{0;4},{0;5}
{1;1},{1;2},{1;3}
{2;1},{2;2},{2;3},{2;4}I guess the question is do I need to figure out the cull pattern- each B may have different lengths...…