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Comment on: Topic 'remove a list of point from another list of point': 70;76;111. 69;78;112. 69;79;113. 68;83;114. 67;85;115. 67;86;116. 68;87;117. 68;88;118. 68;90;119. 69;91;120. 69;92;121. 70;94;222. 69;94;1…; Added by lv-esad at 2:46am on March 13, 2015

Topic: Specific results(outputs) for specific inputs?: 5 15 6 17 7 ... … Any idea how to do this? Thank you.…; Added by djordje at 5:54pm on August 5, 2011

Comment on: Group 'SpiderWeb': ve a Vertex [V] connected to four other Vertexs [N1-N4]. Each of the has a Value: V ... 1 N1 ... 5 N2 ... 3 N3 ... 8 N4 ... 11 The Average Filter would set the Value of [V] to (1+5+3+8+11)/5 = 5,6 The Median Filter would Sort Values and pick the middle one 1,3, [5], 8, 11 Hope that helped...…; Added by Richard Schaffranek to SpiderWeb at 4:44am on August 31, 2012

Topic: Every X items, a new branch?: the number of items and X is NOT constant any help?…; Added by wrogirzymian at 11:04am on April 7, 2012

Comment on: Topic 'Specific results(outputs) for specific inputs?': 13 5 15 6 17 7 ... … But it seems I have not been clear: the input values (3,5,7,9,11,13) should be presented in the way of "number slider" parameter. So by increasing the value of the slider from minimum 3, to 5, 7, 9, 13, 15, 17... I should get an output numbers of 0,1,3,4,5,6,7... So I if choose value 3 on the input "number slider", on the other end, I want 0 as an output. Or if I choose value 5 on the input "number slider", I want 1 as an output, and so on. Is this possible?…; Added by djordje at 6:37pm on August 5, 2011

Topic: Mock-Up due this week: tName_FinalProject_PartD.pdf Below is the desk crit list, please sign up for a spot in the comments below: 1. 2. 3. 4. 5. 6. 7. 8. 9. 10. 11. 12. See you Monday!…; Added by Joseph Iwaskiw to WAAC SPRING 2015 at 11:36am on April 23, 2015

Comment on: Topic 'Path Mapper Component - what are "placeholders"?': where each branch contains all the points generated by dividing each curve, so if you divide into 10 segments, you'll get: {0;0}(N = 11) {0;1}(N = 11) {0;2}(N = 11) {0;3}(N = 11) {0;4}(N = 11) Where the second integer in the curly brackets refers back to the index of the curve in the original list. Another way to look at this data is to see it as a table. It's got 5 rows (one for each original curve) and 11 columns, where every column contains a specific division point. -- David Rutten david@mcneel.com Poprad, Slovakia…; Added by David Rutten at 1:23pm on April 3, 2012

Topic: Cull Pattern: ll these 12500 points. Group 1 would represent the point located at 0, 5, 10, 15, 20 etc. Group 2 - 1, 6, 11, 16, 21 etc. Group 3 - 2, 7, 12, 17, 22 etc. Group 4 - 3, 8, 13, 18, 23 etc. Group 5 - 4, 9, 14, 19, 24 etc. I can create the pattern but the selection of points are all the points in row 0 and then all the points in row 5 and so on. I would like the selection of points to start at the bottom left, and sequentially continue to the right and then continue on the 2nd row (left to right & bottom to top). i am hoping the pattern i am trying to achieve is more understood with the quick screen capture I uploaded. the end goal is to be able to select all the points in the grid that are in each pattern. Thanks in advance for any guidance with this. …; Added by Alyne Rankin at 6:53am on October 11, 2017

Topic: running boolean Toggle in specific order: ggle A 7. Toggle A 8. Toggle 2 9. Toggle 3 10. Toggle A 11. Toggle A 12. Toggle 3 I was thinking to use somehow slider and animate option....but without luck Any idea would be appreciated…; Added by Michal Dengusiak at 7:41am on May 17, 2013

Topic: Complex Data Path Split: gt;>> {1} {2;7} >>>> {2} {2;8} >>>> {3} {2;9} >>>> {4} {3;10} >>>> {0} {3;11} >>>> {1} {3;12} >>>> {2} {3;13} >>>> {3} {3;14} >>>> {4} How to do that !? Thanks in advance :D…; Added by Digit at 12:51am on December 3, 2016