at your original list of numbers, if I am to go through and check manually to see what I should be getting out, I think you should only get a few outputs (which is why I was confused by all the outputs at the end of the definition.
For example, just as an example I started with X1 as 279 (item index 11). When I did the math, the only indexes that I got were 15,28, and 33.
This is because:
since 279 is positive, look for next number that is at least 180 less or 360 more than X1.
the value of 78 (item index 15) is the first value to satisfy this requirement.
Then, since 78 is smaller than 279, we are looking for the next value at least 180 more or 360 less than 78.
The value 272 (item index 28) is that next value.
Then since 272 is larger than 78, we are looking for the next value at least 180 less or 360 more than 272.
The value 52 (item index 33) is the next value.
So the definition should output the following:
indexes 15, 28, 33.
Does that make sense?…
Added by Brian Harms at 4:20pm on December 10, 2011
Delaunay triangulations maximizes the minimum angle of all the angles of the triangles in the triangulation; they tend to avoid skinny triangles.
In order to obtain a valuable (quality) mesh at a given minimum angle for triangles (here 15 degrees), I advise to implement Chew Second Algorithm (see : http://2011.cccg.ca/PDFschedule/papers/paper91.pdf).
Then, the control of triangle lengths should be done by pruning edges below 28 inches.
Do not hesitate to contact me.…
connection, camera, micro. Rhinoceros software; much better with Windows system.
Materials > Materials, equipments and tools needed for making the prototype are included in the course tuition.
Training hours > 72 hours (Part I) and 28 hours (Part II). It is possible to do the full course or just Part I
Certificate It will be provided a certificate by Authorised Rhino Training Center and Rhino FabStudio Official
Instruction Language > English (or Spanish if all the students speak it)
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PART II, optional (On-site / On-line) August 29 - September 2
Schedule*: Monday - Friday 1- 3pm and 4-8pm (Madrid, CEST)…
ceros. Parametrización, panelización y análisis en Grasshopper, así como el proceso de manufactura digital para maquinaria de corte Láser y CNC.
UN solo pago anticipado $4,000.00
Pagos diferidos $4,500.00*
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$4,000.00…
eone would know how to group each data position from each branch ... meaning, for instance, that I have a list of data with 3 branches, each branch containing 28 data instances (see attached image). Now, how would I get the (0;0)+(1;0)+(2;0) to be grouped in a new branch, as well as (0;1)+(1;1)+(2;1) and so on?
Also, I need for the setup to able to take in variables, so that the 3 branches might change to 6, and the 28 data instances might to change to anything between 10 and 100.
Thanks in advance,
/Claus
…
ctorial component to go to higher factorials/permutations just to determine easily permutations. For instance I have 30 tile colors and I wanted to see their permutations quickly, I realize I can use 30*29*28 etc but I thought I could do this using the simple definition that one can see in the pic.
RM
…
29 points vs. 28 points for the 'Base Crv' - not sure what's up with that?
Move the slider in the 'Adjust Seam' group to see parametric design in action!
And just FYI, there are only 12 discontinuity points in the 'Step Crv' so setting the 'Divide Curve' 'Count' slider to 12 looks pretty good to me, except for that extra point.…
Added by Joseph Oster at 12:26pm on January 10, 2016