7, 9, 12 and 13 to be able to rotate freely around the y axis at nodes 2, 3, 6, 7, 10 and 11 respectively. The last 2 conditions, for elements 12 and 13, doesn't give any problems, but the first 4 does.
Any help?
…
oning behind using the equality component to test for even numbers is flawed because of the data matching used by gh. It is testing like this:
0==0 True
2==1 False
4==2 False
6==3 False
etc
.............
Where as a Modulo 2 would work like this
0%2 = 0
1%2 = 1
2%2 = 0
3%2 = 1
4%2 = 0
5%2 = 1
6%2 = 0
7%2 = 1
8%2 = 0
9%2 = 1
......
Also I notice you have some errors in your expressions producing Nulls.
If you want it to be twice the value then you should have 2*D in the Expression and 10*D in the other
....
I attach a working version.…
now I want to combine some branches together ,the rule is : For path{2} contain number 2 and 5, then conbine the two paths together ,and for path{5} includes only 2&5,no other number ,so it's end .For path{3}, includes number 3&6 ,so we go to path{6}, path{6} includes 3&6&18, then wo go to path{18} , path{18} contains a new number 27, so we check path{27} ,path{27} includes only 27&18, no new numbers ,so it is end.
With this logic, path{2}&{5} become one tree finally , the contains is 2&5 ,and so path{3}&{6} &{18} &{27}(the contents is 3,6,18,27), and so others .
so what I want is:
{2}(2,5)+{5}(2,5)={2/5/anything}(2,5) ## the new path index doesnot matter{3}(3,6)+{6}(3,6,18)+{18}(18,27)+{27}(27,18)={3/6/18/27/?}(3,6,18,27) ``````etc
I tried path mapper, but I donot think it can do the trick this time. may be I just miss something very visible?? Awaiting for your kind help~Thanks in advance.…
vector * number
8. number * point
9. point * number
10. complex * complex
11. colour * colour
12. colour * number
13. number * colour
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David Rutten
david@mcneel.com
Seattle, WA…
Added by David Rutten at 10:39pm on November 12, 2010
o now is select and group together list items by their index. {0:0} and {2:0} also {1:0} and {3:0}. They way I'm doing this at the moment is quite complicated and I'm sure there's an easier way to achieve the same result.
maybe someone in here knows a solution?
thanks a lot…
;1},{0;2},{0;3}, (note that the first item is NOT {0,0})
{1;1}{1;2},{1;3},
{2;1},{2;2},{2;3},
{3;1}{3;2},{3;3}...
Well I'll just upload an extract of the definition. The data path should be the same, but with the items in the last path shifted to the first path, and the items in the first path shifted to the second path and so on.
I'll keep trying. …
s 8, 4, 2, 10, 1, 3, 8, 4, 2, 0. But then for the end result to maintain all numbers above 5 but replace all numbers below with a defined number..Let's say zero. So then the list would read...8, 0, 0, 10, 0, 0, 8, 0, 0.…
ents will do or which components will be available.
My problem arises because I want to obtain a list such as the following:
{{6, 5, 4, 3, 2, 1, 2, 3, 4, 5, 6}, {5, 6, 5, 4, 3, 2, 1, 2, 3, 4, 5}, {4, 5, 6, 5, 4, 3, 2, 1, 2, 3, 4}, {3, 4, 5, 6, 5, 4, 3, 2, 1, 2, 3}, {2, 3, 4, 5, 6, 5, 4, 3, 2, 1, 2}, {1, 2, 3, 4, 5, 6, 5, 4, 3, 2, 1}}
Which displayed as a matrix is:
If it were possible to combine GH operations (series, shift list, replace string...) with matrices I think it would be quite powerful. A matrix to list component like those available on scientific calculators, would then translate the matrix to list.
For me, matrices come in handy when dealing with surface patterns.
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Added by Jesus Galvez at 6:46am on November 26, 2012