掌握编程过程中遇到的思路方面和技术方面的问题. 内容包括以下几个方面:
反向逻辑思维能力的培养;
建立清晰的编程逻辑思维能力;
GH 的程序设计理念;
并行数据结构深入理解和控制.
Grasshopper course of McNeel Asia focus on the cultivation of students flexible use of programming techniques, the ability to solve practical problems. Our course deep into the whole process of programming, from programming thinking model, the components principle to usage details do detailed explanation, help students complete mastery programming encountered in the process of thinking and technical aspects, include the following content:
Ability of reverse logical thinking;
Establishment of clear programming logical thinking ability;
The program design concept of Grasshopper;
Understanding parallel data tree structure and how to control it.
更多详细内容... More details…
授课讲师 Instructor 课程由Grasshopper原厂McNeel公司在中国地区的两位 Rhino 原厂技术推广工程师 – Dixon、Jessesn联合授课。课程结束后对达到授课预定目标的学员颁发唯一由Grasshopper原厂认证的结业证书.
Dixon & Jessesn, McNeel Asia Support engineer, by the end of course student who achieve the intended target will get the authentication certificate from McNeel Asia.
课程报名 Register this course 课程即日开始报名, 开课一周前停止报名, 名额满提前报名结束. This course begin to sign up, stop sign up a week ago, with the quota ahead over.
在线报名参加课程...
Sign up to this course…
课程日期 Schedule 7/15-7/20 Beijing 北京 7/26-7/31 Shanghai 上海 7/07-7/12 Shenzhen 深圳
课程范例演示 Samples of Grasshopper course demo
Note: pls follow below comments by Jessesn to see the samples…
ts, a value for each point.This script is wrinting in C#, not C++. And of course, can be done with standard components, perhaps someone else help you with that.…
o three parts:
branch 1:
{0;0} N = 3
{0;1} N = 3
branch 2:
{1;0} N = 5
{1;1} N = 5
branch 3:
{2;0} N = 30
{2;1} N = 30
parthmapper won't change the length of branch, explode tree won't give me two branches in one output
…
13;2} ... 20.{13;12}
21. {21;0}22. {21;1}23. {21;2} ... 41. {21;20}
42. {34;0}43. {34;1}44. {34;2} ... 75. {34;33}
76. {55;0}77. {55;1} ... ....
I want to grab the first 8 [0-7], the next 13[8-20], the next 21[21-42] etc
so i have the (known fibonacci seq) list of numbers on the left here:
C S
8 0
13 8
21 21
34 42
55 76
89 131
144 220
233 364
and i need the list on the right, so that i can select items using a Series (N=1 and S and C from the list above) and a List Item component.
the simple question is:
is there a component that can take a list and accumulate it in this way that I need?
if not, is there anyone that can point me to a simple relevant VB example so i could easily adapt it?
many thanks,
gotjosh…
Pérez Albà McNeel Europe presents Rhino 5.0, Matus Nedecký (flying architecture) and Fabio Palvelli (3D Dreaming) show VRAY for Rhino and rendering services for architecture. We also show the new Wacom Cintiq 22 HD touch.
There are 2 events, the first at 15:00 and the second at 18:30. Places are limited to 30 people each.
As a special event you can switch between the events at a basic coffee seminar "Coffee - from the plant to the cup" part. Coffee Museum in Austrian society and economy museum was founded by Edmund Mayr, who injected together with Arch Wilhelm Holzbauer, the increase of the flak tower in Esterhazy Park. His passion for collecting are also due to the many exhibits that he has collected from all over the world. Additionally Mag. Just shows a quick roundup of "100 Years of Life and Living in Vienna" and how the inventions of Dr. Carl Auer von Welsbach changed the world significantly.
program: 15:00 to 15:45 Presentation software Autodesk Maya 2014 (group 1)
15:45 -. 16:00 Tour "100 years of life and living in Vienna / Dr Carl Auer von Welsbach in the Agricultural Museum (Group 1)
16:00 to 16:45 Presentation software Rhino 5.0 and VRAY (group 1)
5:00 p.m. to 6:15 p.m. basic coffee seminar "Coffee - from the plant to the cup" with Mr Edmund Mayr
18:30 to 19:15 Presentation software Autodesk Maya 2014 (Group 2)
19:15 -. 19:30 Tour "100 years of life and living in Vienna / Dr Carl Auer von Welsbach in the Agricultural Museum (Group 1)
19:30 to 20:15 Presentation software Rhino 5.0 and VRAY (Group 2)
20:15 finger found, drinks and "Come Together"
22:00 End of the event
Participation is FREE, due to the limited number of places but registration is required. To register for the event, we ask you to select the following options:
Online Registration 15:00 http://www.kkkc.at/component/seminar/?task=3&cid=5
Online Registration 18:30 http://www.kkkc.at/component/seminar/?task=3&cid=6
or by email: office@kkkc.at
or Tel: 01-545 78 25…
one, when its one trunk divide the isocurve into 30 parts, then divide each of the 3 branches should be divided into 10, and then the main trunk after they merge back together should be divided into 30.…
Added by Eli Meltzer at 4:05pm on February 9, 2012
ee 3)
{5}
0 15
{6}
0 16
And I want to place points at every possible combination of these coordinates, treating Tree 1 as X coordinates, Tree 2 as Y coordinates, and Tree 3 as Z coordinates. Also, I would like the list of points to be a tree with paths corresponding to the coordinates. Wouldn't it be nice if I could plug these trees into a Point XYZ, with a new "branch cross reference" method, and get the following result?
{0:3:5}
0 {10.0, 13.0, 15.0}
{0:3:6}
0 {10.0, 13.0, 16.0}
{0:4:5}
0 {10.0, 14.0, 15.0}
{0:4:6}
0 {10.0, 14.0, 16.0}
{1:3:5}
0 {11.0, 13.0, 15.0}
{1:3:6}
0 {11.0, 13.0, 16.0}
{1:4:5}
0 {11.0, 14.0, 15.0}
{1:4:6}
0 {11.0, 14.0, 16.0}
{2:3:5}
0 {12.0, 13.0, 15.0}
{2:3:6}
0 {12.0, 13.0, 16.0}
{2:4:5}
0 {12.0, 14.0, 15.0}
{2:4:6}
0 {12.0, 14.0, 16.0}
In this form of cross referencing, every combination of individual branches from the different lists is used as separate input, and the output for each combination is put onto a branch in the result whose path is the concatenation of the input branch paths used.…
Added by Andy Edwards at 7:03pm on November 3, 2009