output will show a tree with 3 branches of 4 integers each that I can pass on to other components. What is the best way to do it?
I have tried creating a tree and using a for loop to do so, but it didn't work.
Thank you for your help.
…
0, 5, 10, 15, 20
1, 6, 11, 16, 21
2, 7, 12, 17, 22
3, 8, 13, 18, 23
4, 9, 14, 19, 24
and if i'm here is because i'm not able... :)
can you help me?
thank you
…
circles that can be populated (for each radius size) is set as an integer (or slider)
(ie. radius 1.5 = 10 , radius 3= 6, radius 6 = 6, radius 9=4)
Conditions are:
1) Each of the circle has a radius of influence,
Radius of influence = double the radius of the circle)
(3, 6, 12, 18)
2) Any overlapping circles in either: Radius of influence or the Circles are removed so that
No circles overlap.
3) There must also be 4 circles set at the corner points of the grid - These must be circles with a radius of 3 or 6
If you can do that I will be amazed as i've been trying for weeks! :(
Ive attached a sketch of what im looking for…
i mean, i want a slider that can do 3 sides, 4 sides, 5, 6, 7, 8, 9 and 10. for the grids because I dont want to use a fixed grid shape such as square grid (4 sides only).
that guarantees structural stability.
This particular structure has been studied by Maurizio Brocato and Lucia Mondardini, it is inspired by a french patent from the 16th century for a flat vault deposited by Mr. Abeille, giving the name 'Abeille vault'.
You can find more info on nexorades here:
http://thinkshell.fr/form-finding-of-nexorades-and-reciprocal-structures/
http://thinkshell.fr/4604/
http://snbr-stone.com/index.php?option=com_content&view=article&id=19&catid=9&Itemid=29
Best,
Romain
…
Thank you Marios,
but I want to put boxes on all the plane: if I divide U domain in 4 parts and V domain in 3 parts I'll have 12 boxes with 12 different heights in W
How can be done?
regards
Maurizio