53 → 53 → 63 → 74 → 74 → 84 → 9
As you can see from the above list the connection sequence comes in waves of three, where each group of similar indices on the left is associated with a group of three incrementing indices on the right.
Some combination of Series components will probably generate this list, but it'll only work for the first ring, the second one will need a different connection pattern. It is perhaps better to just encode the integer pairs by hand. But then you cannot change your mind about the number of sides later.…
Added by David Rutten at 10:39am on October 21, 2015
a follow up question... how do I wrap a list onto itself at a certain frequency?
i.e. I want the list {1;2;3;4;5;6;7;8;9}
to become {1,4,7; 2,6,8; 3,6,9} wrapped every 3rd item
Added by Joshua Jordan at 5:30pm on November 17, 2012
you want each "element" to be a single Item or a single item for ALL elements. See Below
0. 20
1. 30
2. 59
3. 60
4. {9,45,29}
5. 0.0
6. 3.0
7. 6.0
Or
0. 20 30 59 60 {9,45,29} 0.0 3.0 6.0
…
Added by Danny Boyes at 3:13am on October 29, 2013
t case point 3 should be able to move from 20 to 33
so in other word
pt 3 depends on pt 2
the problem is if i only have sliders
pt2 could be 20
and pt 3 could be 20, that is higher than 33
so the loft loops in itself
gracias por tu ayuda
salu2
m…