with 10 ordered curves. These in turn are to be interated in a move slider( 10 vectors).
As I plug these 3 new grafts in the move slider though, these curves all iterated 10 times (100 curves total) instead of being lifted one at a time.
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cture, Rhino treats them as a single flat list. For example a surface can have 10 rows and 6 columns of control-points, resulting in a list of 60 points.
But 10 times 6 isn't the only way to get to 60. If you want to make a surface out of a list of 60 points, you'll also have to tell Rhino how those 60 points should be interpreted in terms of a grid. It could be 2*30, 3*20, 4*15, 5*12, 6*10, and all of the aforementioned products the other way around.
Sometimes there's only one way for a number of points to fit into a rectangular grid. For example if you provide 49 points, then 7*7 is the only way to make it work, but these cases are rare so we always demand you give us all the information required to actually make a rectangular grid of control-points from a linear collection.
As for "Why is it, sometimes we need to attach additional value into it?", this is usually because when you divide a domain or a curve into N segments, you end up with N+1 points. For example take the domain {0 to 5}, and divide it into 5 equal subdomains. You end up with {0 to 1}, {1 to 2}, {2 to 3}, {3 to 4} and {4 to 5}. However there are six numbers that mark the transitions between these domains 0, 1, 2, 3, 4 and 5. This is why you often have to add 1 to the UCount, because the number that controls the UCount often results in N+1 actual points.…
Added by David Rutten at 8:30am on December 25, 2014
. etc. So it's 80020 which is ~1058. Assuming you're allowed to use the same component more than once.
1058 × 1049 = 10107 total possible algorithms. When talking about big numbers I only have three frames of reference. The distance from us to the edge of the observable universe is roughly 1029 millimeters, the observable universe contains 1080 protons and the volume of the observable universe is roughly 5×10105 cubic nanometers. So you could more or less put a different valid Grasshopper algorithm into every cubic nanometer of this universe.
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David Rutten
david@mcneel.com
Poprad, Slovakia…