created surface with sweep and rotate them with number of division. Section curves of 2Railsweep is defined with 3 Point arc and shape is also controlable.
You can change shape by sliding 16 paramteters.
The definition is rather long, hope somebody can modify with more sphiscated manner.
日本語
パラメトリックにボトルデザインをする.ghxファイルを作成しました。ボトルのプロファイルカーブを、参照となる円に対して、高さ、シフト、オフセットでコントロールポイントの位置情報を与えて定義。次にスイープで分割数だけ回転コピーして作成。
スイープの断面、3点円弧で作成し、形状コントロールするようにしています。
ボトル形状は、16のパラメーターをスライドすることで定義出来ます。
…
branches in each A's list of B's, or remove its ends etcso that if I want to remove the last B in every A{0;1},{0;2},{0;3},{0;4},{0;5},{0;6}{1;1},{1;2},{1;3},{1;4}{2;1},{2;2},{2;3},{2;4},{2;5}would become{0;1},{0;2},{0;3},{0;4},{0;5}
{1;1},{1;2},{1;3}
{2;1},{2;2},{2;3},{2;4}I guess the question is do I need to figure out the cull pattern- each B may have different lengths...…
TREE B
{0} n=1 {0;1} n=4
{1} n=1 {0;4} n=4
{2} n=1 {1;1} n=4
{1;2} n=4
{1;3} n=4
{1;4} n=4
{2;1} n=2
{2;2} n=4
{2;3} n=4
{2;4} n=4
Both trees are generated from sliders, so could have any number of branches, although they are tied together. Tree A is a set of division points on a line, Tree B is a set of intersections from lines generated radially from the first (in this case three) points. I am trying to perform a "closest point" operation between the first tree and the second tree-- only, I do not want them to cross list, or long or short list. I want the {0} point to operate with those entries in the 2nd tree that start with {0,x}. So it would look like
{0} --> closest point with {0;1},{0;4}
{1} --> closest point with {1;1},{1,2},{1,3},{1,4} etc
I cannot figure out how this works. What I am visually trying to do is cast rays from a string of points so that they stop when they encounter another curve. I am having trouble picking through the intersection events to get what I want. Check the attached files for some clarity. THANK YOU…
Added by Joshua Jordan at 12:06am on February 5, 2012
mponent it gives you a 10 points surface and then leaves a 4 points one, what if I want to make a 4 points surface and then leave the space of a 10 points one?…
E.g.:
0 2 (A) = 2
1 2+4 (A+B) = 6 (AB)
2 6+4 (AB+C) = 10 (ABC)
3 10+6 (ABC+D) = 16 (ABCD)
etc.
Into a new list numbers:
{2,6,10,16, etc} that adding the previous number with the next number.
Thanks,
daniel
…
lues. What I want to do is combine them so that the structure would be something like:
{4;0}
{4;1}
{4;2}
{4;3}
{5;0}
{5;1}
{5;2}
{5;3}
I tried the method here, but it didn't give me what I wanted, it was just tacking the new values onto the end, and not maintaining their paths. Any help would be appreciated. Thanks!…
Added by Dennis Goff at 8:13am on February 10, 2016
for instance
if i have a bunch of pionts, say "4", i want the connection of them without getting connections within the same 2 points.
the answer should be (4X3) / (1X2).