en 3 of them, and one poolyline between two of them.
It would also be very nice if i could control it so that only the successive ones can be connected
so if {0:0:0} has 8 points and {0:0:1} has 8, as do {0:0:5} and {0:0:6} i would like to have this as two polylines, not one continoous that would in this case jump three branches (or curves that are shorter).
Does this make any sense?…
Added by Dusan Bosnjak at 2:08pm on September 28, 2009
≈ 4.8 " as " x= 4.8 ± a ", do you know what is the min and max for "a"?
and second, i had tried the "round" function, but i faced problem with it too! for example:
if the input is a series as {0.0, 0.5, 1, 1.5, 2, 2.5, ...}
the output for Round(x, 0.5) is : {0, 0, 1, 2, 2, 2, 3, 4, 4, 4, 5, 6, 6, 6, ... }
and for Round(x, 2) the output is : {0.0, 0.5, 1, 1.5, 2, 2.5, ... }
i can't understand the logic that lies behind this function, i think
for Round(x, 0.5) the output must be {0.0, 0.5, 1, 1.5, 2, 2.5, 3, 3.5, 4, 4.5, ... }
and for Round(x, 2) it must be {0.0, 0.0, 2, 2, 2, 2, 4, 4, 4, 4, ... }
so, is there any problem with it, or I misendestood the logic ?…
{0;1;0}N=6
{0;1;1}N=6
{0;1;2}N=5
{0;2;0}N=7
{0;2;1}N=8
{0;2;2}N=9
Can you shift and wrap any of the paths A B or C?
Say if I wanted to shift and wrap B by 1 to get the following...
{0;0;0}N=7
{0;0;1}N=8
{0;0;2}N=9
{0;1;0}N=3
{0;1;1}N=2
{0;1;2}N=5
{0;2;0}N=6
{0;2;1}N=6
{0;2;2}N=5…
rated by "<" symbols. Examples: "2<10", "2<4<10", "Pow(2, 1)<5*Sin(3)<10".
The entered text contains 2 or 3 segments separated by two or more consecutive dots. Examples "2..10", "2..4..10", "Pow(2, 1)....5*Sin(3)..10".
If only two segments are provided, then the initial value will be the same as the minimum value. If a bounds number or a default value is written as a simple number, then the number of decimal places will be harvested. I.e. "2..4..10" is not the same as "2..4..10.00" as the former will result in an integer slider and the latter in a slider with two decimal places.
--
David Rutten
david@mcneel.com
Poprad, Slovakia…
Added by David Rutten at 10:08am on February 15, 2013
53 → 53 → 63 → 74 → 74 → 84 → 9
As you can see from the above list the connection sequence comes in waves of three, where each group of similar indices on the left is associated with a group of three incrementing indices on the right.
Some combination of Series components will probably generate this list, but it'll only work for the first ring, the second one will need a different connection pattern. It is perhaps better to just encode the integer pairs by hand. But then you cannot change your mind about the number of sides later.…
Added by David Rutten at 10:39am on October 21, 2015