- 100.
After that, I want to separate it into 5 different lists in spesific thickness.
in this case of 0-100 so it would be :
1. if the distance 0 - 20 then the thickness is 5
2. if the distance 21 - 40 then the thickness is 10
3. if the distance 41 - 60 then the thickness is 15
4. if the distance 61 - 80 then the thickness is 20
5. if the distance 81 - 100 then the thickness is 25
But, the problem is the list of distance isn't static between 0-100. It could be 5 - 250 / 3.5-175/etc.....
Could you help me how to make the expression?? Is this possible if I make one expression?
thank you.
Z.
nb: distance and thickness hasn't mathematical relation.…
Added by ZAQI FATHIS at 8:43am on November 27, 2013
(without the flaps on the edge). 1. How can I make this "piece" behave like a segment with multiple folds? 2. How can I add more of the same segments (join them on the sides) in order to create a closed object? 3. I would also like to be able to change the number of border edges as well and to be able to control the position of those points in order to make differently shaped "planar pieces" and different objects in the end.
All ideas are appreciated. Thank you. Jiri…
it is important how you create the surface in rhino!1 Create a planar triangle curve and use surface from planar crv.2. srf by 3 or 4 points. choose 4 points!
select
question about setting threshold in octopus. sDA and ASE output ranges from 0 to 100. Am I right to say, for my LEED calculation, sDA max 55 and ASE max 10 are the threshold I should stick with?
Regards, Cheney
…
e image searches on the forum are useful as well:
site:grasshopper3d.com +Boolean +union +fails
https://www.google.com/search?q=site+grasshopper3d+com+Boolean+unio...
…
Added by Nik Willmore at 12:13am on February 27, 2016
eone would know how to group each data position from each branch ... meaning, for instance, that I have a list of data with 3 branches, each branch containing 28 data instances (see attached image). Now, how would I get the (0;0)+(1;0)+(2;0) to be grouped in a new branch, as well as (0;1)+(1;1)+(2;1) and so on?
Also, I need for the setup to able to take in variables, so that the 3 branches might change to 6, and the 28 data instances might to change to anything between 10 and 100.
Thanks in advance,
/Claus
…
data tree shift list component from pt.1 and then duplicate graft component and connect it to shifted list
4. now get loft component and with shift key pressed add data from "grafted tree" and "shifted and grafted" component
5. after all you should get path mapper, and if after lofting data tree looks like {A;B} then write in path mapper {A;B} -> {A} (double click this guy to get type in windows)
This should work but I write it on the fly, so not 100% sure (file needed to check)…