or each branch goes to col 1, element 2 to col 2 and so on. The issue I am having is how to deal with branches that have less than 5 elements. Notice how in the attachment the number 8 is at row 2 where I want it to be in row 3.…
Added by jon kontuly at 1:03pm on September 30, 2014
se presentarán una pieza cortada con láser o CNC.Extracto de TemarioIntroducción Fundamentos Grasshopper Image Sampler V-Ray Interiores Que es es CNCFundamentos Interfase Visualización - Grasshopper V-Ray Exteriores Arboles de datos Corte, Laser e impresión 3dTeoria de Curvas Componentes y parametros Listas de datos V-Ray Materiales Clusters ToleranciasTranspocición Vectores y reticulas -Atractores Series y rangos Teoria de Superficies Conexiones Estrategias de modelado para manufacturaSimetrias Transpocisión parametrica Formulas Panelizacion Teoría de Ensambles Teoría de archivos para corteAtractores Cull Random Información del taller:Fechas: del 8 al 26 de Junio de 2015Sesiones: 8 de 3 hrs y presentación finalDuración: 27 hrs.Días: Lunes,Miércoles y ViernesHorario: de 19:00 a 22:00 hrsPrecio : $4,500 Apartado: $2,000Pago oportuno (antes del 1 de Junio): $3,500PAQUETESTaller y Rhino 5.0 Educativa: $6,500.00 Taller y Rhino 5.0 Comercial: $21,000.00 *Sólo hacemos reembolso en cancelaciones con un mínimo de 15 días previos al taller.info@dimensiontallerdigital.comtel oficina (55) 50160634…
掌握编程过程中遇到的思路方面和技术方面的问题. 内容包括以下几个方面:
反向逻辑思维能力的培养;
建立清晰的编程逻辑思维能力;
GH 的程序设计理念;
并行数据结构深入理解和控制.
Grasshopper course of McNeel Asia focus on the cultivation of students flexible use of programming techniques, the ability to solve practical problems. Our course deep into the whole process of programming, from programming thinking model, the components principle to usage details do detailed explanation, help students complete mastery programming encountered in the process of thinking and technical aspects, include the following content:
Ability of reverse logical thinking;
Establishment of clear programming logical thinking ability;
The program design concept of Grasshopper;
Understanding parallel data tree structure and how to control it.
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授课讲师 Instructor 课程由Grasshopper原厂McNeel公司在中国地区的两位 Rhino 原厂技术推广工程师 – Dixon、Jessesn联合授课。课程结束后对达到授课预定目标的学员颁发唯一由Grasshopper原厂认证的结业证书.
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课程日期 Schedule 7/15-7/20 Beijing 北京 7/26-7/31 Shanghai 上海 7/07-7/12 Shenzhen 深圳
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he sunPath component works. For example if you want to simulate the hours from 8 to 16 it means you want 8 hours from 8 to 9, from 9 to 10,.... from 15 to 16 (8 hours duration period) so you get from the sunPath component (using default timeStep 1) the 9 sun position/vectors 8 9 10 11 12 13 14 15 16 (in the image the yellow suns). The things is that if you ask for a smaller timeStep for example 3 = 20 mins then the additional sun position (in the image the orange suns) are added also after the time limit of h16 so probably when you don't want/need. I understand that when you input a time period there is the ambiguity if the hours are the just 9 (the 9 inputs) or the 8 hours included between pairs of hours, but I would make in a way that it is possible to chose if the extra timeStep after the last hour are added or not. Thank you for your comments.
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ems in the same way. Lofting was particularly difficult, you had to have a separate loft component for every lofted surface that you wanted to generate because the component would/could only see one large list of inputs. Then came along the data structures in GH v0.6 which allowed for the segregation of multiple input sets.
If you go to Section 8: The Garden of Forking Paths of the Grasshopper Primer 2nd Edition you will find the image above describing the storing of data.
Here you will notice a similarity between the path {0;0;0;0}(N=6) and the pathmapper Mask {A;B;C;D}(i). A is a placeholder for all of the first Branch structures (in this case just 0). B is a place holder for all the second branch structures possibly either 0, 1 or 2 in this case. And so forth.
(i) is a place holder for the index of N. If you think of it like a for loop the i plays the same role. For the example {A;B;C;D}(i) --> {i\3}
{0;0;0;0}(0) --> {0\3} = {0}
{0;0;0;0}(1) --> {1\3} = {0}
{0;0;0;0}(2) --> {2\3} = {0}
{0;0;0;0}(3) --> {3\3} = {1}
{0;0;0;0}(4) --> {4\3} = {1}
{0;0;0;0}(5) --> {5\3} = {1}
{0;0;0;1}(0) --> {0\3} = {0}
{0;0;0;1}(1) --> {1\3} = {0}
{0;0;0;1}(2) --> {2\3} = {0}
{0;0;0;1}(3) --> {3\3} = {1}
{0;0;0;1}(4) --> {4\3} = {1}
{0;0;0;1}(5) --> {5\3} = {1}
{0;0;0;1}(6) --> {6\3} = {2}
{0;0;0;1}(7) --> {7\3} = {2}
{0;0;0;1}(8) --> {8\3} = {2}
...
{0;2;1;1}(8) --> {8\3} = {2}
I'm not entirely sure why you want to do this particular exercise but it goes some way towards describing the process.
The reason for the tidy up: every time the data stream passes through a component that influences the path structure it adds a branch. This can get very unwieldy if you let it go to far. some times I've ended up with structures like {0;0;1;0;0;0;3;0;0;0;14}(N=1) and by remapping the structure to {A;B;C} you get {0;0;1}(N=15) and is much neater to deal with.
If you ever need to see what the structure is there is a component called Param Viewer on the first Tab Param>Special Icon is a tree. It has two modes text and visual double click to switch between the two.
Have a look at this example of three scenarios in three situations to see how the data structure changes depending on what components are doing.
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Thanks, Chris!
I put a slider into the U-count and tried values from 1 to 60 (I have 9 input curves). I get surfaces at 2, 4, 8, 19, and 38. All are nonsensical surfaces though...
wim