ft , 4:3 (to use GH); it could be nice dock icon bars to the left or right working with laptop screen and put it on top working in GH with the 4:3 one.
This feature is cool, but not really usefull.
Best Regards.…
opper is all these values "recognizing" as similar/same.
I got list of results (n) with following values:
0. -3.2584e-9 1. -4.4992e-9 2. -6.7220e-9 3. -4.5154e-9 4. -4.3325e-9 5. -2.2496e-9 6. -2.2385e-9 7. -6.7525e-9 8. -4.5154e-9
Even though most of these values (maybe all of them) "go" into the second group:
(10^(-9)≤n) and (n>10^(-4))
Grasshopper recognizes all of them as members of the first group:
10^(-4)≥n
I am aware that this kind of very small values are unusual, and maybe Grasshopper is not made for it. But is there any way this can be done?
Take a look:
Thank you.…
ements between mid axes of elements ( being perpendicular to both). On the attached image, the links are the small elements connectiong nodes 4 to 5, 6 to 7 and 8 to 9. All nodes (1 to 9 including 1', 2', 3') are defined in Karamba as fixed supports but nodes 1,1', 2, 2', 3, and 3' have hinges added with the beam joint component. The freed rotations are shown on the figure.
I wondered if that was the correct way of defining such a structure in Karamba bearing in mind that nodes 1', 2' and3' are free nodes in the reality.
Thanks again for your help !
Yousef…
Hi,
in this moment I can't understand the table.
I have two list A and B both with 3 item, so I have 9 combinations. why the table has 4 column and not 3?
st with 6 branches the first 3 having 8 items and the last three having 4 items . I really want to say take list 1 and add list 2 onto the bottom of it so i get a list with 9 branches each with 4 items?
As always thanks wonderful forum!…
i mean, i want a slider that can do 3 sides, 4 sides, 5, 6, 7, 8, 9 and 10. for the grids because I dont want to use a fixed grid shape such as square grid (4 sides only).
Integer = 0 To 9
val *= 2
lst.Add(val)
Next
Since val is a ValueType, when we assign it to the list we actually put a copy of val into the list. Thus, the list contains the following memory layout:
[0] = 2
[1] = 4
[2] = 8
[3] = 16
[4] = 32
[5] = 64
[6] = 128
[7] = 256
[8] = 512
[9] = 1024
Now let's assume we do the same, but with OnLines:
Dim ln As New OnLine(A, B)
Dim lst As New List(Of OnLine)
For i As Integer = 0 To 9
ln.Transform(xform)
lst.Add(ln)
Next
When we declare ln on line 1, it is assigned an address in memory, say "24 Bell Ave." Then we modify that one line over and over, and keep on adding the same address to lst. Thus, the memory layout of lst is now:
[0] = "24 Bell Ave."
[1] = "24 Bell Ave."
[2] = "24 Bell Ave."
[3] = "24 Bell Ave."
[4] = "24 Bell Ave."
[5] = "24 Bell Ave."
[6] = "24 Bell Ave."
[7] = "24 Bell Ave."
[8] = "24 Bell Ave."
[9] = "24 Bell Ave."
To do this properly, we need to create a unique line for every element in lst:
Dim lst As New List(Of OnLine)
For i As Integer = 0 To 9
Dim ln As New OnLine(A, B)
ln.Transform(xform)
lst.Add(ln)
Next
Now, ln is constructed not just once, but whenever the loop runs. And every time it is constructed, a new piece of memory is reserved for it and a new address is created. So now the list memory layout is:
[0] = "24 Bell Ave."
[1] = "12 Pike St."
[2] = "377 The Pines"
[3] = "3670 Woodland Park Ave."
[4] = "99 Zoo Ln."
[5] = "13a District Rd."
[6] = "2 Penny Lane"
[7] = "10 Broadway"
[8] = "225 Franklin Ave."
[9] = "420 Paper St."
--
David Rutten
david@mcneel.com
Poprad, Slovakia…
Added by David Rutten at 6:26am on September 9, 2010