number of divisions on that curve as in the defintion (i.e. by 4). The offset in the def is slightly different and should cull two or three more curves as in the lists that show my aim below.
Basically I want to look into each branch of the groups of points from each closed curve . Marking in a list whether it contains a one or a zero (0= outside 1 = coincidents).
{0;0}0. 21. 22. 23. 2 {0;1} 0. 01. 22. 03. 2 {0;2}0. 01. 02. 03. 0 {0;3}0. 21. 22. 23. 2 {0;4}0. 21. 22. 23. 2 {0;5}0. 21. 22. 23. 2 {0;6}0. 01. 22. 23. 1 {0;7}0. 21. 22. 03. 0 {0;8}0. 21. 22. 23. 2 {0;9}0. 21. 22. 23. 2 {0;10}0. 21. 22. 23. 2 {0;11}0. 21. 22. 23. 2 {0;12}0. 21. 22. 23. 2 {0;13}0. 01. 22. 23. 0 {0;14}0. 21. 22. 23. 2
I want to create a list from these points. That marks each curve that pokes out, in a cull pattern as such:
20022210222202
Using a 1 where there are co-incidents in the curve points and the boundary. A 2 for true (outside points) and a 0 for containment. So I might be able to use the 1 in future developments - however if a true false list is easiest I can live with that.
So could I use F(x) function? - to look for 0 or 1's in each bunch of points and thus list as such for a cull pattern? or will Path mapper help me here? Or can I rely on simply grafting and splitting??
I am usure of the neatest solution and would love to learn. Hope you can direct me.rgrds
J.…
this, you'll have no horizontal force at the roller, but you will have it at the pinned support. If you wouldn't, then the structure will be displaced.
Usually, in 2 dimensional structures, if you want to know if an articulated structure is isostatic (as opposed to hyperstatic, which is what you have right now) is to use the following formula:
b+c-2·n=0;
b being the number of bars, c the number of constraints you have and n the number of nodes. In your case: b=19, c=3 (displacements constrained in X, Z at your pinned support and only constrained in Z at your roller support) and n=11, so: 19+3-2·11=0.
I recommend you to download the app SW Truss, as it's very useful to check your results instantly.…
ult, my 3dm is very large.
Another problem, when the fonction is ok, the draw in grasshopper is ok, when i bake i have only a litte part of the opération.....
If you could help me, thank you
[Edit] Here the description in the null item :
{0;0}0. Brep: brep.m_T[43047] trim is not valid. trim.m_type = seam, the edge is manifold, but brep.m_L[trim.m_li=1114].m_type is not outer.brep.m_L[1114] loop is not valid. brep.m_T[loop.m_ti[21]=43047] is not valid.brep.m_F[0] face is not valid. brep.m_L[face.m_li[1114]=1114] is not valid.ON_Brep.m_F[0] is invalid.1. 2. 3. 4. 5. 6. 7. 8. 9. 10. 11. 12. …
r surfaces by EP results' components.
Having set a period from 9:00 to 19:00 for a single day (10th december), and using a slider from 0 to 10 (11 values, 0 is 9:00), the following mismatch occurs:
setting value 0 works for surface temperature but not for mean radiant temperature (warning says "stepofSimulation is outside the bounds of the comfResultMTX", but I do have 11 values from radiant temp matrix).
setting value 1 is rendered as "hour 2 of simulation" for surface temperature (FIG 1) and as "9:00" of radiant temperature (FIG 2).
It seems there is a slide of 1 hour. How should I interpret this?
Kind regards,
artemátyika…
Added by artemátyika at 3:34pm on February 2, 2019
ta.
Take the following example.
I have two curves referenced with a Crv Param this creates a single path with 2 items {0}(N=2).
If I divide these Curves by 10 segments I end up with 2 Paths of 11 points each {0;0}(N=11) and {0;1}(N=11)
If I want each point to be handled separately I can Graft a branch to hold each point. So I get 22 Paths looking like {0;0;0}(N=1), {0;0;1}(N=1).....{0;1;10}(N=1).
Each path is therefore the address of a particular item or items of interest.
The Param Viewer can be found Params>Special>Param Viewer and can be viewed either as a list of Paths or graphically by a double click.
Also note that the Fancy Wires display the structure of a stream of data. Single wire = Single Data Item, Double Wire = Multiple Data on single Path and Double Dashed Wire = Multiple/Single Data on Multiple Paths…
rcle A 0---1---2Circle B 0---1---2---3---4---5---6---7---8---9---10---11I was actually trying to connect through separated lines, point (A,0) to (B,11) and (B,1),point (A,1) to point (B,3) and (B,5), and (A,2) to (B,7) and (B,9).I was able to do it using a list item selecting the points and creating a line between them, but i would be to long to do it if i would like to divide in many more points, and try to connect them using list item... i went looking around for a bit, i think its possible to do it with a path mapper or a flip matrix, althought i have no clue how to make it.
You will find enclosed, some screenshots...If anyone could give me any tip, i thank you all in advance.Have a nice day.+Joan…
Added by Joan tarragon at 7:38am on December 5, 2011
1) to each length. For example you have a length of ten and you create a domain from 9 to 11. later you want to group all lines by as less as possible domains.
If you have a look to the image...you see 6 lines and their red dotted ranges. to group them by the domain of 3 and 5 would be the best result with the less domains. (here 2)
if you would use the domain of line 0,1 or 3 you could not include line 4 and you would have 3 instead of just 2 groups.....
later on it is important for me to group as much as possible lines in less as possible domains.
I hope this is somehow understandable.…
Added by horst Becker at 11:15am on November 2, 2013
1
with three sliders 8:
000, 001, 010, 011, 100, 101, 110, 111
with 120 slider -> 2^120 = 1.329 * 10^36
http://www.wolframalpha.com/input/?i=+2%5E120
2.
How do you combine the fitness function? Galapagos only takes 1 number as a fitness so this might be a problem as well, simple mass addition might not do the trick.
…