a specific domain, for example:
0.) 0 to 1 -----> 11 random values from 0 to 1 (0.245,0.678,0.36,0.78,.28,0.18........)
1.) 1 to 2 -----> 11 random values from 1 to 2 (1.26,1.36,1.01,1.68,1.26,1.96.........)
3.) 2 to 3 -----> 11 random values from 2 to 3 (2.96,2.45,2.78,2.56,2.98,2.10..........)
4.) 3 to 4 and so on where I have a data set containing 11 paths with 11 values and the values fall within the specific domain.
Like my post above I have the correct path but I need to feed it the correct seed to get different values for each number. I tried grafting a series similar to the last post but it scrambles my data. Thanks so much for the help!
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7, 9, 12 and 13 to be able to rotate freely around the y axis at nodes 2, 3, 6, 7, 10 and 11 respectively. The last 2 conditions, for elements 12 and 13, doesn't give any problems, but the first 4 does.
Any help?
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created surface with sweep and rotate them with number of division. Section curves of 2Railsweep is defined with 3 Point arc and shape is also controlable.
You can change shape by sliding 16 paramteters.
The definition is rather long, hope somebody can modify with more sphiscated manner.
日本語
パラメトリックにボトルデザインをする.ghxファイルを作成しました。ボトルのプロファイルカーブを、参照となる円に対して、高さ、シフト、オフセットでコントロールポイントの位置情報を与えて定義。次にスイープで分割数だけ回転コピーして作成。
スイープの断面、3点円弧で作成し、形状コントロールするようにしています。
ボトル形状は、16のパラメーターをスライドすることで定義出来ます。
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ces which is 3, 45 from first branch and 4, 5, 47 from second and so on. It means I need to choose branch 3 and 45 from list B using list A indices 3 and 45
I need it to be added after choosing the branch from list B, which is (branch 3 + branch 45) of list B. As you can see each branch in list B contains 101 items so if I add branch 3 and branch 45 it would give 101 items and added in same order.
Finally I need it like a list containing these 63 branches same count as list B but after adding branches that we got from list A.
Please help me with this, I tried using tree split could not achieve it still.
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in the desired order.
0 = 0
1 = 1
2 = 6
3 = 7
4 = 8
5 = 9
6 = 12
7 = 13
8 = 2
9 = 3
10 = 4
11 = 5
12 = 10
13 = 11
Where the first number is the index and the second number is the actual sorting key. Then you sort these keys while sorting your curves in parallel using the A input of the Sort component.
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David Rutten
david@mcneel.com
Poprad, Slovakia…