hi, i want to split a list in as much parts as the parameter (slider) shows.if the slider shows 3 then in three parts, if the slider shows 5 then in 5 parts etc...Is it possible?thanks
hink you need recursion to modify the random seed; many other ways to accomplish that (use the length of each curve as the seed, for example).
Using multiples of twelve makes it harder for me to grasp the essence of the matter; another way of looking at it is that you want to generate random integers from 2 to 5 (24,36, 48 and 60) and have them add up exactly to curve lengths of 5 (x12=60), 9 (x12=108) or 14 (x12=168).
So you want to generate random numbers until their sum ('Mass Addition') plus 5 is equal to or greater than the curve length (5, 9 or 14). The last number in the series is then not random but just the difference between the two.
For example, for curve length = 5 (x12=60), there are only three possible numbers that can be used as the first in the sequence: 2, 3 or 5. If it's 5, you're done. If it's 2, the second number is 3 (5-2), if it's 3, the second number is 2 (5 - 3). You can't use '4' at all because the remainder, 1 (x12=12) isn't one of your solution options.
There is no point in generating the last number randomly, eh?
P.S. You didn't use 'Internalize data' for the 'Curve (Crv)' param in your GH file.…
Added by Joseph Oster at 2:29pm on September 12, 2015
ep is to understan the logics of what you want to do, in your case, build 4 point surfaces (u also need to know the right direction to build the surfaces). Then you can write an hipotetic list (by hand in a paper) of what you want. In your case the list was (0, 1, 3, 2) (2, 3, 5, 4) (4, 5, 7, 6), etc... if you can imagine building 2 lists, each one with the sequences (0, 2, 4, 6, etcc) and (1, 3, 5, 7, etc..) then you can manage with shift and graft to finally have four lists. A( 0 1 2 3 ...) B (1 3 5 etc..) C(3 5 7 etc..) D (2 4 6 etc..). And to achieve the 2 first lists, you need to get the odd and the pair numbers. The cull pattern does that amazingy well. With a pattern True-False you get de pair numbers, and with the False-True pattern you get de odd numbers.
Hope it was clear enough…
Added by Pep Tornabell at 5:32am on November 19, 2009
per components.
I have attached a 3dm file and a picture so you guys can see what I am talking about.
I have previously translated boxes into breps, which i did with this code:
Dim bbx As New box(pl, New interval(-.5, .5), New interval(-.5, .5), New interval(-.5, .5)) Dim ms As New Mesh() ms.Vertices.AddVertices(bbx.GetCorners) ms.Faces.AddFace(0, 1, 2, 3) ms.Faces.AddFace(0, 1, 5, 4) ms.Faces.AddFace(1, 2, 6, 5) ms.Faces.AddFace(2, 3, 7, 6) ms.Faces.AddFace(3, 0, 4, 7) ms.faces.addface(4, 5, 6, 7) ms.Normals.ComputeNormals()
ms.Compact()
I have tried to do something similar with this specific example, and I now that meshes only consist of quads or triangles, so i broke down the geometry into quads without any succes.
Looking foreward to any suggestions.
- Jens…
nts me this:
[[0], [0, 1], [0, 1, 2], [0, 1, 2, 3], [0, 1, 2, 3, 4], [0, 1, 2, 3, 4, 5], [0, 1, 2, 3, 4, 5, 6], [0, 1, 2, 3, 4, 5, 6, 7]]
this is what I wanted but how to convert this to tree in grasshopper?
In grasshopper I just get:
8x IronPython.Runtime.List…
g definition but in diva for grasshopper in material it just appear dusty_med and not metal_railings and metal_treads. How I should write the correct definition?
void brightfunc dusty_med4 dirt dirt.cal -s 101 .25
dusty_med metal metal_railings005 .7 .7 .7 .3 .2
dusty_med metal metal_treads005 .5 .5 .5 .3 .2…
} (N=11) {0;1} (N=11) {0;2}(N = 11) {0;3}(N = 11) {0;4}(N = 11)
2. I run the Points that are coming out from the Divide Curve Components through the Path Mapper components with this definition:
{A;B} (i) > {A} (i)
3. I run data coming out from Path Mapper component through:
a) Parameter Viewer component and the result is:
{0} N=11 (data with 1 branches)
b) Point > Panel and the result is:
collection of 11 point (N=11) which is the exactly the same as the collection of point belonging to {0;4} (N = 11).
So, here is the question:
why the collection of points coming out from the Path Mapper {A;B} (i) > {A} (i) component is the same as the collection of points belonging to the curve {0;4}(N = 11) ?
Anyway ... It 's the first time I ask a question here... so I would like to thank you for what you do with your work! Thank you! You are really great!…