e 5. after 13 seconds create value 6. Area 2 change depending on value etc.
on german
danke für ihr hilfe.Aber es soll jede Fläche einzeln nacheinander angesteuert und verändert werden. Verlauf:1. Fläche 1 ansteuern2. nach 13 sekunden wert erzeugen 3. Fläche 1 je nach wert verändern 4. Fläche 2 ansteuern5. nach 13 sekunden wert erzeugen 6. Fläche 2 je nach wert verändern und so weiter…
Hi,
I want to solve a 3x3 system of linear equations (with a the gaussian elimination method?) of the type:
1 2 3 | 1
4 2 6 | 1
1 0 1 | 1
Any help would be appreciated. M.
Added by Mecky Reuss at 10:46am on August 15, 2015
I could type X=6 to get an X vector of length 6, for example.
2. It would be great to enable this functionality with clusters, so that one non-geometry input per cluster could be activated in this way. ("My custom cluster = 40")
3. Maybe it's just me, but "set default color" for panels doesn't seem to work yet.
4. allowing other simple data types might be useful in some situations - "Domain = -10 to 10", "Boolean = false" etc. As it stands now I just fill such values into a panel when I need to enter them quickly; maybe this in itself is sufficient.
Thanks for all the amazing work, and enjoy your month away!…
{4}-0;3
{5}-6;7
{6}-5;7
{7}-5;6
Here it can be shown that there are two subgraphs containing 0,1,2,3,4 and 5,6,7. How can I use spiderweb (either using scripting or the components) to give me this result when I have many more vertices??
Thanks,
Sam…
Int32 = 0 To y.count - 1
Dim c As Char = Convert.ToChar(y(i).substring(7, 1))
Dim d As Char = Convert.ToChar(y(i).substring(8, 1))
Dim p As Integer
If c = ";" Then
p = convert.ToInt32(y(i).substring(6, 1))
Else If d = ";" Then
p = convert.ToInt32(y(i).substring(6, 2))
Else
p = convert.ToInt32(y(i).substring(6, 3))
End If
Dim path As New EH_Path(p)
For j As int32 = sum To sum + z(i) - 1
tree.Add(x(j), path)
Next
sum = sum + z(i)
Next
A = tree…
;-2;-1;0;1;2;3) and beside that i don't want to have 0 as a result.
So at the End I would like to have only 6 numbers: -3;-2;-1;1;2;3
I already came to an result with integer numbers but it actually only rounded up the random results. when one of the results was -0.473 it ended up as 0.
I'm sure it's pretty easy to solve, I'm just missing something.
thx for help…
91 Items on 13 Branches (7 rows * 13 columns = 91 points)
Path Structure is:
The Address of all those items on the Data Tree.
Think of the "{0;0;0}" format as an addressing system.
The not obviously necessary extra 0's at this point represent the equivalent to Country and State (or something like that)
So the first point in your grid in Column 0 Row 0 has the address {0;0;0}(0)
The next point up is {0;0;0}(1) until you get to the to of the column {0;0;0}(6)
The Next column over is {0;0;1} with points ranging from (0) to (6)
We continue like this until we get to the last column Last Point {0;0;12}(6)
Therefore a relative path from the first point in the first column to the last point in the last column is {0;0;+12}(+6}
Does this make sense so far?…
6, 7, 8, 9, 10, 12, 14, 16, 18, 20, 22, 24, 26, 28, 30, etc
In addition to the components in the attached file, I have also tried using Cull Index but that did not do much. I tried using a number slider set to whole numbers with the range equal to the values I have set up in the integer, but it just increases the size by 1 every time. Any help on steps in the right direction would be great thanks.…